Answer:
C≈50.13
Step-by-step explanation:
The answer is C≈50.13
Answer:
1.2 , 0.4
Step-by-step explanation:
Each number is divided by 3.
97.2 ÷ 3 = 32.4
32.4 ÷ 3 = 10.6
10.6 ÷ 3 = 3.6
3.6 ÷ 3 = 1.2
1.2 ÷ 3 = 0.4
Answer:
<h3> 1/√3</h3>
Step-by-step explanation:
Given the expression tan (-150), from trigonometry identity, tan(-θ) = -tanθ
Hence tan (-150) = - tan 150
First is to find the value of tan 150.
tan 150 = tan (180-30)
tan (A+B) = (tan180 - tan30)/1+tan180tan30
tan (180-30) = (0 - 1/√3)/1+0(1/√3)
tan (180-30) = -1/√3/1
tan (180-30) = -1/√3
Since tan 150 = -1/√3
-tan 150 = -(- 1/√3)
-tan 150 = 1/√3
Since -tan 150 = tan (-150) = 1/√3
Hence the exact value of tan (-150) is 1/√3
Part A:
The distance travelled by an object at time t is given by: d = st
where d is the distance, s is the speed and t is the time.
Given that the cheetah travels a maximum of 70mph, the distance travelled by the cheetah travelling at 70mph at time t is given by d = 70t
There are 60 mins in one hour, so the distance given in miles per minutes is d = 70/60t = 1.167 miles per minutes.
Part B:
Given that t = 10 minutes, the distance covered by the cheetah in 10 minutes is d = 1.167 x 10 = 11.67 miles.
Part C:
<span>If the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes, then the number of minutes the cheetah have traveled in the first 8 minutes</span> is given by
d = 1.167 x 8 = 9.33 miles.
Part D:
If the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes, then<span> the number of minutes the cheetah have traveled in the second 8 minutes is given by
d = 40/60 x 8 = 5.33 miles
Part E:
</span><span>The distance the cheetah traveled in the first 8 minutes more than in the second 8 minutes </span>is given by
9.33 miles - 5.33 miles = 4 miles.
Part F:
The ratio of the distance travelled in the first 8 minutes to the distance travelled in the next minutes is given by
9.33 : 5.33 = 1.75 : 1.
Therefore, <span>the distance traveled by the cheetah during the first 8 minutes is 1.75 times greater than the distance traveled during the second 8 minutes.
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