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3 years ago

How can you use ratios and rates to solve real- world problems?

1 answer:

8 0

Usually, They make tables of equivalent ratios relating quantities with whole-number measurements, find missing values in the tables, and plot the pairs of values on the coordinate plane.

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The opposition of 135

zysi [14]

Answer:

i think you r missing some questions r u doing degrees or something else i am not sure

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Points b,d, and f are midpoints of the sides of triangle ACE. EC=30 and DF= 17 find AC

Margaret [11]

Answer:

Your answer should be AC=2DF=34

Step-by-step explanation:

5 0

2 years ago

Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck

Nimfa-mama [501]

$\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}$
$\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}$

Now, isolate the variables, so you can integrate.
$(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}$
$\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}$
$2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C$

$4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C$
$y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C$

$y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$
$y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$

At x = 1, y = 0.
$0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$
$-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0$
$\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C$
$0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C$
$C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}$
$C = -\frac{\pi}{2}$

$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

6 0

3 years ago

ASAP<br> -WILL MARK BRIANIST

tamaranim1 [39]

Answer:

Step-by-step explanation:

im not sure but the question asks about types of bread, since none are listed, i am assuming they all have a different price so the $1 bread $2 bread $3 bread and $5 bread... sorry i couldn't help better!

6 0

2 years ago

Write the slope-intercept form of the equation of the line through the given point with the given slope. through: (1, 1), slope

RSB [31]

Answer:

y=2x-1

Step-by-step explanation:

y-y1=m(x-x1)

y-1=2(x-1)

y=2x-2+1

y=2x-1

Please mark me as Brainliest if you're satisfied with the answer.

7 0

2 years ago