Answer:
No
Step-by-step explanation:
Given the following quartile values :
Q1 = 351, Q2 = 355. and Q3 = 357
Values below : Q1 - 1.5*IQR
Values above : Q3 + 1.5*IQR
IQR = Q3 - Q1
IQR = 357 - 351 = 6
THEREFORE ;
Lower boundary = 351 - (1.5 * 6) = 351 - 9 = 342
Upper boundary : 357 + (1.5 * 6) = 357 + 9 = 366
Hence, any value below the lower boundary value or above the upper boundary value would be considered an Outlier. Only values which lie within the lower and upper boundary values are not considered as outliers.
Therefore, a fill volume of 353 mL will not be considered an Outlier as it lies in between the lower and upper boundary values.