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Gwar [14]
3 years ago
10

In a particular​ year, a total of 46,601 students studied in two of the most popular host countries when traveling abroad. If 84

83 more students studied in the most popular host country than in the second most popular host​ country, find how many students studied abroad in each country. There were ____ students who studied abroad in the most popular host country.
Mathematics
1 answer:
Ilya [14]3 years ago
3 0

Answer:

31,783.5

Step-by-step explanation:

Half of 46601 = 23300.5

23300.5 + 8483 =31783.5

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Is the orthocenter of a triangle on the inside ?
likoan [24]

Answer:

It turns out that all three altitudes always intersect at the same point - the so-called orthocenter of the triangle. The orthocenter is not always inside the triangle. If the triangle is obtuse, it will be outside. To make this happen the altitude lines have to be extended so they cross.

7 0
3 years ago
Read 2 more answers
T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is


K(x)= \frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}


The given curve is y=7e^{x}


{y}''=7e^{x}\\ {y}'=7e^{x}


k(x)=\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}


{k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}

For Maxima or Minima

{k(x)}'=0

7(e^x)(1+49e^{2x})(98e^{2x}-1)=0

→e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0

e^{x}=0  ,  ∧ 1+49e^{2x}=0   [not possible ∵there exists no value of x satisfying these equation]

→98e^{2x}-1=0

Solving this we get

x= -\frac{1}{2}\ln{98}

As you will evaluate {k(x})}''<0 at x=-\frac{1}{2}\ln98

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[-\frac{1}{2}\ln98,1/√2]

k(x)=\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}

k(x)=\frac{7}{\infty}

k(x)=0







5 0
3 years ago
an electrition charged $70 for 2 hours of work and 115 for 5hours of work write an equtionto find the cost for y and xk
Westkost [7]

\bf \begin{array}{ccll} \stackrel{x}{hours}&\stackrel{y}{cost}\\ \cline{1-2} 2&70\\ 5&115 \end{array}~\hspace{10em}(\stackrel{x_1}{2}~,~\stackrel{y_1}{70})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{115}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{115-70}{5-2}\implies \cfrac{45}{3}\implies 15


\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-70=15(x-2)\implies y-70=15x-30 \\\\\\ y=15x+40\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}


as you already know, a direct proportional variation has a constant of variation "k", y = kx, which in this case that'd be the slope, namely 15.

7 0
3 years ago
Need help with equations with variables on both sides, giving 100 points, tysm if you help :) 6 (2x-4) = 8(x +2) A. 3 B. 10 C. 2
scoundrel [369]

Answer:

B. 10

C. All real numbers.

Step-by-step explanation:

6 (2x-4) = 8(x + 2)

Distribute the numbers outside of the factors:

12x - 24 = 8x + 16

Subtract both sides by '8x'

12x - 8x - 24 = 8x - 8x + 16

4x - 24 = 16

Add '24' to both sides:

4x = 40

Divide both sides by 4:

x = 10. Therefore, <u>B. 10</u> is the correct answer.

3(4p - 2) = -6(1 - 2p)

Distribute the numbers similarly to the example before:

12p - 6 = -6 + 12p

Subtract '12p' from both sides:

12p - 12p -6 = -6 + 12p - 12p

0 -6 = -6

Add '6' to both sides:

0 - 6 + 6 = -6 + 6

0 = 0

Therefore, the solution consists of <u>all real numbers.</u>

3 0
3 years ago
WILL GIVE BRAINLIEST 10 POINTS Select all ordered pairs that satisfy the function y= -1/2x + 4
Ulleksa [173]
B I think but i could be totally wrong
3 0
2 years ago
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