Assuming that all the grapes have the same probability of being randomly picked:
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How to find the probabilities?</h3>
We know that there are 8 green grapes and 15 red grapes on the bowl, so there is a total of 23 grapes.
a) Here we need to find the probability that both grapes are green. Remember that the probability of getting a green grape is equal to the quotient between the number of green grapes and the total number of grapes, this is:
P = 8/23
But then he must take another, because he already took one, the number of green grapes is 7, and the total number of grapes is 22, so for the second grape the probability is:
P' = 7/22.
The joint probability is the product of the two individual probabilities:
prob = (8/23)*(7/22) = 0.11
b) For the first green grape we know that the probability is:
P = 8/23
Then he must get a red grape. There are 15 red grapes and 22 grapes in total, so the probability is:
P' = 15/22
Then the joint probability is:
prob = (8/23)*(15/22) = 0.24
If you want to learn more about probability:
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Answer:
Step-by-step explanation:
It is given that,
Mass of benzene, m = 0.1 L
Mass, m = 36.4 g
We know that, 1 L = 1000 cm³
0.1 L = 100 cm³
The density of an object is equal to its mass divided by its volume. So,
So, the density of benzene is 
.
Ans: B
The method (a^2-b^2) is considered as one of the many ways of factorisation.
Hope this can help.
Answer:
It seems that problem might have an error.
population = 600 * e ^ (.02*t) where e = 2.718281828459
So, at day 1 we have
day 1 population = 600 * 2.718281828459 ^(.02*1) = 32.62
day 2 population = 600 * 2.718281828459 ^(.02*2) = 88.67
We can see that the population doubles in less than one day but the lowest of those multiple choices is 34.657 days
Step-by-step explanation:
Answer:
0.2381 = 23.81%
Step-by-step explanation:
To calculate this probability, we can calculate the probability of each student of the 3 students interviewed being from middle georgia state college.
If inicially there are six students from middle georgia state college among the nine students, the probability of the first student chosen being from middle georgia state college is 6/9.
Then, as one student was already picked, we have now 5 students from middle georgia state college in a total of 8 students, so the probability of the second student will be 5/8.
In the same way, the third student will be picked in a group of 7 students, where 4 are from middle georgia state college, so the probability is 4/7.
Multiplying all the probabilities, we have the probability of all three students interviewed being from middle georgia state college:
P = (6/9) * (5/8) * (4/7) = 120/504 = 0.2381 = 23.81%
