Question

calculate the base and perimeter of an isosceles triangle having area 192 cm square. ln which the ratio of base and height is 3:2​

Answer 1

Step-by-step explanation:

Given that,

The area of an isosceles triangle, A = 192 cm²

The ratio of base and height is 3:2.

The area of a triangle is given by :

$A=\dfrac{1}{2}\times b\times h$

Let base = 3x and height = 2x

So,

$192=\dfrac{1}{2}\times 3x\times 2x\\\\3x^2=192\\\\x^2=64\\\\x=8$

Base = 3x = 3(8) = 24 cm

Height = 2x = 2(8) = 16 cm

Let equal sides be 16 cm and base be 24

So,

Perimeter = sum of all sides

= 16+16+24

= 56 cm

Hence, this is the required solution.