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kobusy [5.1K]
3 years ago
10

2 FEBRUARY 1ST SYSTEM APPLICATION POP QUIZ

Mathematics
2 answers:
Sidana [21]3 years ago
7 0

Answer:

the answer is 25 i think

nignag [31]3 years ago
5 0
$7.5 for the two hats, but 3.75 for each hat
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The school football team needs to raise at least $850 to buy new practice equipment. The team received a donation of $125 and al
navik [9.2K]

Answer:

182

Step-by-step explanation:

850-125=725

725/4=181.25

So you need at least 182 tickets sold.

4 0
3 years ago
Pentagon W X Y Z V is translated up and to the right to pentagon W prime X prime Y prime Z prime V prime. Pentagon W prime X pri
marshall27 [118]

Answer:

A rotation of 180* around point Z

Step-by-step explanation:

The pentagon is translated then rotated around z

4 0
4 years ago
Read 2 more answers
Problem Solving REAL WORLD 14. 13. Jerome is making prizes for a game at the school fair. He has two bags of different candies,
Artemon [7]

Answer: There are 5 candies of first type and 4 candies of second type.

Step-by-step explanation:

Since we have given that

Number of pieces of candy of first type = 15

Number of pieces of candy of second type = 20

We need to find the greatest number of pieces possible.

So, Greatest number of pieces = H.C.F. of 15 and 20 = 5

So, there are 5 greatest number of pieces possible.

Number of candies of first type in this piece = \dfrac{15}{5}=5

Number of candies of second type in this piece = \dfrac{20}{5}=4

Hence, there are 5 candies of first type and 4 candies of second type.

6 0
3 years ago
Ordena esto <br>4/8, <br>9/16<br>3/4<br>4/6<br>​
alina1380 [7]

Answer:

If you were to order them least to greatest, it would be:

4/8 < 9/16 < 4/6 < 3/4

If you were to order them greatest to least, it would be:

3/4 > 4/6 > 9/16 > 4/8

8 0
3 years ago
There are 14 NBA teams who do not make
leva [86]
In this situation, the order matters, since being 1st pick is not the same as being 2nd or 3rd. Therefore, there are 14 choices for the first pick, 13 remaining for the second pick, and 12 for the third pick. This is equivalent to the permutation 12P3.
12P3 =  \frac{12!}{(12-3)!} = 12(11)(10) = 1320 ways

(If order did not matter, this would use a combination.)

8 0
3 years ago
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