5x^4(x^3+8x+6) this is the correct answer
Answer:Hope This Helps ☺️
Step-by-step explanation:
She is not correct because she did not substitute the same number in both expressions in Step 1
Step-by-step explanation:
CASE 1: substitute 1 for x to both sides of the equations
L.H.S
-(4x-5)+2(x-3)
-(4 (1) - 5)+ 2(1-3) = - (-1) + 2(-2) = 1 - 4 = -3
R.H.S
-2x - 5
-2(1) - 5 = -2-5 = -7
Hence for x= 1
-(4x-5)+2(x-3) ≠ -2x -5
Because -3 ≠ -7
CASE 2: substitute -1 for x to both sides of the equations
L.H.S
-(4x-5)+2(x-3)
-(4 (-1) - 5)+ 2(-1-3) = - (-9) + 2(-4) = 9 - 8 = 1
R.H.S
-2x - 5
-2(-1) - 5 = 2-5 = -3
Hence for x= -1
-(4x-5)+2(x-3) ≠ -2x -5
Because 1 ≠ -3
Answer:
She is not correct because she did not substitute the same number in both expressions in Step 1
Between 0.5 and 0.6 can be an infinity.
<em><u>ex:</u></em><u /><u><em /></u><em />
0.51
0.52
0.517
0.5169889549.......
0.5999999999..........
etc.
Answer:
{-1, 3, 7, 11, 15}
Step-by-step explanation:
f(x) = 2x − 1, {0, 2, 4, 6, 8}
f(0) = 2*0 − 1 = 0 - 1 = -1
f(2) = 2*2 − 1 = 4 - 1 = 3
f(4) = 2*4 − 1 = 8 - 1 = 7
f(6) = 2*6 − 1= 12 - 1 = 11
f(8) = 2*8 − 1= 16 - 1 = 15
2x +4y =10x-3y =12
2x +4y =12 -----eq. 1
10x-3y =12 -------eq.2
2x =12 -4y [using eq. 1]
x = (12-4y)/ 2
= 6 -2y
Now, substitute the value of x in eq. 2
10 (6-2y)-3y =10
60 -20y -3y =10
-23 y = 10 -60
y = -50 / -23
y = 50/23
Now, substitute this value of y in any equations given above
10 x-3 (50/23) =12
10x - (150/23)= 12
x= 426/230
