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MA_775_DIABLO [31]

3 years ago

9

In a bag of marbles, image are red, image are blue, image are green, and image are yellow. You pick a marble without looking. Wh

at color marble are you MOST likely to choose?

1 answer:

marysya [2.9K]3 years ago

3 0

Answer:

red

Step-by-step explanation:

1/2 is larger than 1/4, 1/6, and 1/12 meaning the chance of pulling red is greater than getting blue, green, or yellow.

hope i helped you!

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A housepainter mixed 5 gal of blue paint with every 9 gal of yellow paint in order to make a green paint. Which ratio of gallons

BlackZzzverrR [31]

Answer:

C

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3 years ago

A group of children, 6 to 10 years old, were asked how many video games they owned. The scatter plot shows the results.

eimsori [14]

The answer is 10.<span>Think of the outlier as in the dot that's off-topic out of the entire graph. </span>

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3 years ago

How much sides do a pectagan has

siniylev [52]

A pentagon has 5 sides.

Hope this helped :)

5 0

4 years ago

Read 2 more answers

perform all the steps to evaluate this expression. (6^7)(3^3)/(6^6)(3^4) What is the value of the expression?

tatuchka [14]

Answer:

8

Step-by-step explanation: i got it wrong and it tole me the answer.

4 0

3 years ago

What is the Standard Form of the line with x-intercept of 6 and y-intercept of 5?

kolbaska11 [484]

keeping in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$\bf \stackrel{\textit{x-intercept}}{(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})}\qquad \stackrel{\textit{y-intercept}}{(\stackrel{x_2}{0}~,~\stackrel{y_2}{5})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{6}}}\implies -\cfrac{5}{6}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{5}{6}}(x-\stackrel{x_1}{6}) \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{6}}{6(y-0)=6\left(-\cfrac{5}{6}(x-6) \right)}\implies 6y=-5(x-6) \\\\\\ 6y=-5x+30 \implies 5x+6y=30$

4 0

3 years ago