Keith's bank account starts with $250 and he adds $150 to it every month. If <em>m</em> is the number of months that have passed, then the amount of money (in dollars) in his account is given by
250 + 150<em>m</em>
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Victoria's account starts with $2000 and she removes half of it each month. So after <em>m</em> months, her account has a value of
2000/2^<em>m</em>
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If you were to plot these amounts, then
(a) Keith's account's value is indeed linear - TRUE
(b) Keith is constantly adding money to his account, so its value is increasing - FALSE
(c) Victoria's account's value involves an exponential expression - TRUE
(d) Victoria is removing money, so the value is decreasing - TRUE
Your answers are correct except for (c).
Two is less than three which is also less than 5.
When put into a number line from 0 to 10, it shows that 2 is closest to 0 while 5 is closest to 10 and three, will be in between 2 and 5. This shows that as you go from 2 to 3, the number increased and, it continues to increase when you go from 3 to 5. This shows that 2 is less than 3 and 3 is less than 5.
Answer:
C(x) = 7.5k + 2400 is the expense equation.
Step-by-step explanation:
The fixed cost per month = $2,400
Cost of producing each shoe = $7.5
Here, let k be the number of shoes produced per month .
So, the monthly expense
= Fixed Cost + (Number of shoes produced per month x Cost per shoe)
or, C(x) = $2,400 + ( k x $7.5)
or, C(x) = 7.5k + 2400 is the expense equation.
Answer:
No, they are not equivalent
Step-by-step explanation:
8x + 3(x + y)
8x + 3x + 3y
11x + 3y
7x + 7y + 4x + 4y
11x + 11y
They are not equivalent because in one of the equations, the like terms add up to 11y which is different from the other equation which adds up to 3y.
I hope this helps.
Answer:
Step-by-step explanation:
To find the LCM of 1,2,12,30,84,165 you must first find the prime factors of 12,30,84 and 165
12| 2 30| 2 84| 2 165| 3
6 | 2 15 | 3 42| 2 55 | 5
3 | 3 5 | 5 21 | 3 11 | 11
1 1 7 | 7 1
1
Now we look for common and uncommon factors with their greatest exponent
LCM(1,2,12,30,84,165)
Common factors with their greatest exponent: 
Uncommon factors with their greatest exponent: 
