Answer:
The vapor pressure for the first solution at 20°C is 17.48 Torr.
The vapor pressure for the second solution at 20°C is 17.49 Torr.
Explanation:
1) mass of solute that is glucose = 10 g
Moles of glucose ,
Mass of water = m
Volume of water = V = 1L = 1000 mL
Density of water = 1 g/ml
Moles of water =
Vapor pressure of the solution =
Vapor pressure of the pure solvent that is water =
Mole fraction of solute=
The vapor pressure for the first solution at 20°C is 17.48 Torr.
2 ) mass of solute that is sucrose= 10 g
Moles of sucrose ,
Mass of water = m
Volume of water = V = 1L = 1000 mL
Density of water = 1 g/ml
Moles of water =
Vapor pressure of the solution =
Vapor pressure of the pure solvent that is water =
Mole fraction of solute=
The vapor pressure for the second solution at 20°C is 17.49 Torr.
Answer:
Yes is incorrect
Explanation:
not all veins carry blood rich in CO2 , the pulmonary vein carries blood with O2 which means that not all veins carry blood rich in CO2
Tin (Sn), a chemical element belonging to the carbon family, Group 14 (IVa) of the periodic table.
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The compound that ontains the most deactivated aromatic ring is the one called Nitrogen dioxide also knwon as NO2. Let me explain a little bit more about the aromatic rings. These rings are simple aromatics, or arenes, that consist of a conjugated planar ring system. Nitrogen generally is a simple aromatic ring that can be heterocyclic because containsnon-carbon ring atoms. The rings of the nitrogen can be separated into basic aromatic rings and that is why this ompound is also refered as a deactivated aromatic ring.
Answer:
Even the most powerful light-focusing microscopes can't visualise single atoms. What makes an object visible is the way it deflects visible light waves. Atoms are so much smaller than the wavelength of visible light that the two don't really interact. To put it another way, atoms are invisible to light itself.
Explanation:
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