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kvv77 [185]
4 years ago
7

Elements that form ionic bonds generally have how many valence electrons?

Chemistry
1 answer:
asambeis [7]4 years ago
7 0

Answer:

they should have a number that can completely transfer and fill the other atom

Explanation:

example:

sodium(2.8.1)and Chlorine(2.8.7)the sodium will give chlorine the 1 valence electrobo so they both become stable(2.8)±and(2.8.8)–

magnesium(2.8.2)and oxygen(2.6)same way as above to abtain mg(2.8)±²and oxygen(2.8)–²

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What is base unit used to measure volume?
Minchanka [31]

Answer:

SI unit

Explanation:

the base unit of volume in the SI system is the cubic meter

5 0
3 years ago
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The formation of a solid, also known as a _____, is an indication of a chemical change.
elena-14-01-66 [18.8K]

Answer: precipitate

Explanation: Chemical change is a change in which the chemical composition of the atoms changes. The following changes are seen when chemical reaction takes place:

1) Release or absorption of heat

2) Formation of solid or a precipitate

2AgNO_3(aq)+BaCl_2(aq)\rightarrow 2AgCl(s)+Ba(NO_3)_2(aq)

3) Change in color

4) Production of gas

4 0
3 years ago
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What is the concentration of h+ ions in a solution of hydrochloric acid that was prepared by diluting 15.0 ml of concentrated (1
il63 [147K]
HCl is a monoprotic acid, which means that each mole of HCl releases one mole of hydrogen ions upon dissociation. Therefore, we calculate the moles of HCl present using:

Moles = Molarity * Volume (in liters)

Moles = 11.6 * 0.015
Moles = 0.174 moles of HCl = moles of H+ ions

Now, we use the same formula to calculate the molarity of the new solution, since the number of moles remains constant.

0.174 = M * 0.5
M = 0.348 M

The molarity of the new solution is 0.348
7 0
3 years ago
Chromium-51 is a radioisotope that is used to assess the lifetime of red blood cells The half-life of chromium-51 is 27.7 days.
8090 [49]

Answer:

11.9g remains after 48.2 days

Explanation:

All isotope decay follows the equation:

ln [A] = -kt + ln [A]₀

<em>Where [A] is actual amount of the isotope after time t, k is decay constant and [A]₀ the initial amount of the isotope</em>

We can find k from half-life as follows:

k = ln 2 / Half-Life

k = ln2 / 27.7 days

k = 0.025 days⁻¹

t = 48.2 days

[A]  = ?

[A]₀ = 39.7mg

ln [A] = -0.025 days⁻¹*48.2 days + ln [39.7mg]

ln[A] = 2.476

[A] = 11.9g remains after 48.2 days

<em />

8 0
3 years ago
Can somebody please help me with this question, I'm very confused! I thought i did it right because i found Kb and the conc. of
andrew-mc [135]
Let's investigate the substances involved in the reaction first. The compound <span>CH3NH3+Cl- is a salt from the weak base CH3NH2 and the strong acid HCl. When this salt is hydrated with water, it will dissociate into CH3NH2Cl and H3O+:

CH3NH3+Cl- + H2O </span>⇒ CH3NH2Cl + H3O+

Nest, let's apply the ICE(Initial-Change-Equilibrium) table where x is denoted as the number of moles used up in the reaction:

                 CH3NH3+Cl- + H2O ⇒ CH3NH2Cl + H3O+
Initial                  0.51                             0               0
Change                 -x                             +x             +x
-------------------------------------------------------------------------------
Equilibrium        0.51 - x                         x               x

Then, let's find the equilibrium constant of the reaction. Since the reaction is hydrolysis we use KH, which is the ratio of Kw to Ka or Kb. Kw is the equilibrium constant for water hydrolysis which is equal to 1×10⁻¹⁴. Since the salt comes from the weak base, we use Kb. Since pKb = 3.44, then. 3.44 = -log(Kb). Thus, Kb = 3.6307×10⁻⁴ 

KH = Kw/Kb = (x)(x)/(0.51 - x)
1×10⁻¹⁴/ 3.6307×10⁻⁴ = x²/(0.51-x)
x = 3.748×10⁻⁶

Since x from the ICE table is equal to the equilibrium concentration of H+, we can find the pH of the aqueous solution:

pH = -log(H+) = -log(x)
pH = -log ( 3.748×10⁻⁶)
pH = 5.43
6 0
3 years ago
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