Carbon has 4 valence electrons, oxygen has 6
They exist in the outer orbitals
The balanced chemical reaction for the complete combustion of C4H10 is shown below:
C4H10 + (3/2)O2 --> 4CO2 + 5H2O
The enthalpy of formation are listed below:
C4H10: -2876.9 kJ/mol
O2: none (because it is pure substance)
CO2: -393.5 kJ/mol
H2O: -285.8 kJ/mol
The enthalpy of combustion is computed by subtracting the total enthalpy formation of the reactants from that of the products.
ΔHc = (4)(-393.5 kJ/mol) + (5)(-285.8 kJ/mol) - (-2876.9 kJ/mol)
= -<em>126.1 kJ</em>
Thus, the enthalpy of combustion of the carbon is -126.1 kJ.
Answer:
option C = Reactant: 4NH₃ + 6NO → product: 5N₂ + 6H₂O
Explanation:
Chemical equation:
NH₃ + NO → N₂ + H₂O
Balanced chemical equation:
4NH₃ + 6NO → 5N₂ + 6H₂O
Ammonia is react with nitrogen mono oxide and produced nitrogen and water.
Ammonia and nitrogen monoxide are reactants while water and nitrogen are product.
Four number of moles of ammonia react with six nitrogen monoxide and produced five mole of nitrogen and six mole of water.
