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worty [1.4K]
3 years ago
14

What is the formula and valency of thiosulphate ​

Chemistry
1 answer:
tatuchka [14]3 years ago
6 0
Formula: NA2S2O3. Valency: 2
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The sample of 15.0 g of KCl is dissolved into a solution with a total volume of 250.0 mL. What is the molarity of KCl in the sol
lina2011 [118]

Answer:

0.805 M.

Explanation:

Hello!

In this case, since the molarity of a solution is computing by dividing the moles of solute over the volume of solution in liters (M=n/V), for 15.0 g of potassium chloride (74.55 g/mol) we compute the corresponding moles:

n=15.0gKCl*\frac{1molKCl}{74.55gKCl}=0.201molKCl

Next, since the volume is 0.2500 in liters, the molarity turns out:

M=\frac{0.201mol}{0.2500L} \\\\M=0.805M

Best regards!

3 0
3 years ago
An analytical chemist is titrating of a solution of propionic acid with a solution of 224.9 ml of a 0.6100M solution of propioni
Svetllana [295]

<u>Answer:</u> The pH of acid solution is 4.58

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}    .....(1)

  • <u>For KOH:</u>

Molarity of KOH solution = 1.1000 M

Volume of solution = 41.04 mL

Putting values in equation 1, we get:

1.1000M=\frac{\text{Moles of KOH}\times 1000}{41.04}\\\\\text{Moles of KOH}=\frac{1.1000\times 41.04}{1000}=0.04514mol

  • <u>For propanoic acid:</u>

Molarity of propanoic acid solution = 0.6100 M

Volume of solution = 224.9 mL

Putting values in equation 1, we get:

0.6100M=\frac{\text{Moles of propanoic acid}\times 1000}{224.9}\\\\\text{Moles of propanoic acid}=\frac{0.6100\times 224.9}{1000}=0.1372mol

The chemical reaction for propanoic acid and KOH follows the equation:

                 C_2H_5COOH+KOH\rightarrow C_2H_5COOK+H_2O

<u>Initial:</u>          0.1372         0.04514  

<u>Final:</u>           0.09206          -                0.04514

Total volume of solution = [224.9 + 41.04] mL = 265.94 mL = 0.26594 L     (Conversion factor:  1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{salt}]}{[acid]})

pH=pK_a+\log(\frac{[C_2H_5COOK]}{[C_2H_5COOH]})

We are given:  

pK_a = negative logarithm of acid dissociation constant of propanoic acid = 4.89

[C_2H_5COOK]=\frac{0.04514}{0.26594}

[C_2H_5COOH]=\frac{0.09206}{0.26594}

pH = ?  

Putting values in above equation, we get:

pH=4.89+\log(\frac{(0.04514/0.26594)}{(0.09206/0.26594)})\\\\pH=4.58

Hence, the pH of acid solution is 4.58

7 0
3 years ago
Ferrous ammonium sulfate is what kind of test method.
ratelena [41]
Two things

Ferrous Ammonium Sulfate is a pale green or blue-green powder or sand-like solid. It is used in photography, analytical chemistry, and Iron-plating baths.

An FAS-DPD titration is as simple as a test for total alkalinity or calcium hardness. A buffered DPD indicator powder is added to a water sample and reacts with chlorine to produce the pink color characteristic of the standard DPD test.

Hope this it gang
3 0
2 years ago
Calculate the volume of mercury with a density of 14.6 g/mL and a mass of 1.00 g. Please include a numeric value only with signi
Ne4ueva [31]
The answer is 0.06849315

5 0
3 years ago
Write the balanced net reaction for the following half cells: <br> Sn2+ / Sn<br> Cr2+ / Cr
GuDViN [60]

The balanced net reactiion for the following half cells will be

Sn + Cr²⁺   --->  Sn²⁺  +  Cr

<h3>What are Half cells ?</h3>

A half cell is one of the two electrodes of an electrochemical cell.

An electrochemical cell comprises two half cells, where every half cell contains an electrode and an electrolyte.

A salt bridge or direct contact is needed to connect two half cells.

The balanced net reactiion for the given half cells will be

Sn + Cr²⁺   --->  Sn²⁺  +  Cr

Learn more about Half cell here ;

brainly.com/question/1313684

#SPJ1

4 0
2 years ago
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