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Vlad1618 [11]
3 years ago
7

The sequence 200, 100, 50, 25, ... has a common ratio of

Mathematics
1 answer:
disa [49]3 years ago
5 0

Answer:

200/2 = 100

100/2 = 50

50/2 = 25

Everything is being divided by two

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A video game club charges $8 per month as a membership fee, plus $2.75 for each game rental. Eugenie plans to join and rent no m
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22 dollars

Step-by-step explanation:

2.75x5=13.75 dollars

$13.75+$8.00=$21.75

Round it up to the closest number which is $22

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Estimate the value of 68x401÷198
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Round all of the numbers to the nearest 10 then solve the problem like normal
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Lori has 60% of the book to read. If she has read 120 pages how many pages does she still have to read
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Ok, so 120 pages plus the 60% of the book she has left to read will give the total number of pages.

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A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa
Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is  α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion  

p(private) be the proportion of alumni of the private university who attended at least one class reunion  

Hypotheses are:

H_{0}: p(public) = p(private)

H_{a}: p(public) ≠ p(private)

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of  public university students who attended at least one class reunion  (\frac{808}{1311}=0.616)
  • p2 is the sample proportion of private university students who attended at least one class reunion  (\frac{647}{1038}=0.623)
  • p is the pool proportion of p1 and p2 (\frac{808+647}{1311+1038}=0.619)
  • n1 is the sample size of the alumni from public university (1311)
  • n2 is the sample size of the students from private university (1038)

Then z=\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}} =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.  

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4 years ago
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