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2 years ago

The regular price of a hoodie is $70. There is a sale price of 25% OFF the regular price. What is the sale price?

Mathematics

2 answers:

dusya [7]2 years ago

7 0

Answer:

$52.50

Step-by-step explanation:

bija089 [108]2 years ago

5 0

Answer:

$52.5

Step-by-step explanation:

75% of 70 is 52.5, the reason I am finding 75% of 70 is 75% is 25% off

(100 - 25 = 75)

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Bob had three carries of 8 yards each and 5 carries of 6 yards each in a recent football game. what was rushing average(average

Sedaia [141]

3 carries of 8 yds.....3 * 8 = 24 yds
5 carries of 6 yds.....5 * 6 = 30 yds

so we have a total of 8 carries for 54 yds..

54/8 = 6.75 <== average yds per carry

8 0

3 years ago

Read 2 more answers

A tank contains 60 kg of salt and 1000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain

MissTica

Answer:

(a) 60 kg; (b) 21.6 kg; (c) 0 kg/L

Step-by-step explanation:

(a) Initial amount of salt in tank

The tank initially contains 60 kg of salt.

(b) Amount of salt after 4.5 h

$\text{Let A = mass of salt after t min}\\\text{and }r_{i} = \text{rate of salt coming into tank}\\\text{and }r_{0} =\text{rate of salt going out of tank}$

(i) Set up an expression for the rate of change of salt concentration.

$\dfrac{\text{d}A}{\text{d}t} = r_{i} - r_{o}\\\\\text{The fresh water is entering with no salt, so}\\ r_{i} = 0\\r_{o} = \dfrac{\text{3 L}}{\text{1 min}} \times \dfrac {A\text{ kg}}{\text{1000 L}} =\dfrac{3A}{1000}\text{ kg/min}\\\\\dfrac{\text{d}A}{\text{d}t} = -0.003A \text{ kg/min}$

(ii) Integrate the expression

$\dfrac{\text{d}A}{\text{d}t} = -0.003A\\\\\dfrac{\text{d}A}{A} = -0.003\text{d}t\\\\\int \dfrac{\text{d}A}{A} = -\int 0.003\text{d}t\\\\\ln A = -0.003t + C$

(iii) Find the constant of integration

$\ln A = -0.003t + C\\\text{At t = 0, A = 60 kg/1000 L = 0.060 kg/L} \\\ln (0.060) = -0.003\times0 + C\\C = \ln(0.060)$

(iv) Solve for A as a function of time.

$\text{The integrated rate expression is}\\\ln A = -0.003t + \ln(0.060)\\\text{Solve for } A\\A = 0.060e^{-0.003t}$

(v) Calculate the amount of salt after 4.5 h

a. Convert hours to minutes

$\text{Time} = \text{4.5 h} \times \dfrac{\text{60 min}}{\text{1h}} = \text{270 min}$

b.Calculate the concentration

$A = 0.060e^{-0.003t} = 0.060e^{-0.003\times270} = 0.060e^{-0.81} = 0.060 \times 0.445 = \text{0.0267 kg/L}$

c. Calculate the volume

The tank has been filling at 6 L/min and draining at 3 L/min, so it is filling at a net rate of 3 L/min.

The volume added in 4.5 h is

$\text{Volume added} = \text{270 min} \times \dfrac{\text{3 L}}{\text{1 min}} = \text{810 L}$

Total volume in tank = 1000 L + 810 L = 1810 L

d. Calculate the mass of salt in the tank

$\text{Mass of salt in tank } = \text{1810 L} \times \dfrac{\text{0.0267 kg}}{\text{1 L}} = \textbf{21.6 kg}$

(c) Concentration at infinite time

$\text{As t $\longrightarrow \, -\infty,\, e^{-\infty} \longrightarrow \, 0$, so A $\longrightarrow \, 0$.}$

This makes sense, because the salt is continuously being flushed out by the fresh water coming in.

The graph below shows how the concentration of salt varies with time.

3 0

2 years ago

Condense the expression to the logarithm of a single quantity.

kherson [118]

$\dfrac 12 \log_3 x - 2\log_3 (y +8)\\ \\=\log_3 x^{\tfrac 12}- \log_3(y+8)^2~~~~~~~~~~~~~~~~~~;[\log_b m^n = n \log_b m]\\\\=\log_3 \left( \dfrac {x^{\tfrac 12}}{y+8)^2} \right)~~~~~~~~~~~~~~~~~~~~~~~~;\left[\log_b \left( \dfrac mn \right) = \log_b m - \log_b n \right]$

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2 years ago

If F denotes a temperature in degrees Fahrenheit and C is the same temperature measured in degrees Celsius, then F and C are rel

madreJ [45]

Step-by-step explanation:

F= 9/5(C + 32)

5/9 F = C + 32

C = 5/9 F - 32

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3 years ago

If the average adult produces $110,000 of output per year, how much output is lost annually as a result of adult deaths from sec

posledela

The answer to the given question above would be $47,859,000,000 or $48 billion. Given that the average adult produces $110,000 of output per year, the amount of output that is lost annually as a result of adult deaths from secondhand smoke is $48 billion.
600,000 total deaths
165,000 children 
435,000 adults 
435,00 times $110,00 output per year = $47,859,000,000
Hope this helps.

3 0

3 years ago

The regular price of a hoodie is $70. There is a sale price of 25% OFF the regular price. What is the sale price?​

The regular price of a hoodie is $70. There is a sale price of 25% OFF the regular price. What is the sale price?