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PtichkaEL [24]
3 years ago
6

The regular price of a hoodie is $70. There is a sale price of 25% OFF the regular price. What is the sale price?​

Mathematics
2 answers:
dusya [7]3 years ago
7 0

Answer:

$52.50

Step-by-step explanation:

bija089 [108]3 years ago
5 0

Answer:

$52.5

Step-by-step explanation:

75% of 70 is 52.5, the reason I am finding  75% of 70 is 75% is 25% off

(100 - 25 = 75)

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A country's population in 1990 was 132 million. In 1998 it was 137 million. Estimate the population in 2003 using the exponentia
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140 million.I guess.
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There are nickels, dimes, quarters in a large piggy bank, for every 2 nickels there are 3 dimes, for every 2 dimes there are 5 q
Alex

There are 80 nickels and 120 dimes and 300 quarters in piggy bank

<em><u>Solution:</u></em>

Given that,

For every 2 nickels there are 3 dimes ,

So, ratio of nickel to dime will be 2 : 3

Also for every 2 dimes there are 5 quarters

So, ratio of dime to quarters is 2 : 5

Let us first find the ratio of nickles to dimes to quarters

nickel : dime = 2 : 3

dime : quarters = 2 : 5

\frac{nickel}{dime} = \frac{2}{3}

nickel = \frac{2}{3} dime

\frac{dime}{quarter} = \frac{2}{5}

quarter = \frac{5}{2}dime

So,

nickel : dime : quarter = \frac{2}{3}dime : dime : \frac{5}{2}dime\\\\nickel : dime : quarter = \frac{2}{3} : 1 : \frac{5}{2}\\\\nickel : dime : quarter = 4 : 6 : 15

Thus nickel : dime : quarters = 4 : 6 : 15

Now, let the number of nickel be 4x

Let the number of dimes be 6x

Let the number of quarters be 15x

From given question,

There are 500 coins in all.

number of nickel + number of dimes + number of quarters = 500

4x + 6x + 15x = 500

25x = 500

x = 20

Thus,

number of nickel = 4x = 4(20) = 80

number of dimes = 6x  = 6(20) = 120

number of quarters = 15x = 15(20) = 300

Thus there are 80 nickels and 120 dimes and 300 quarters in piggy bank    

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If a ray QR bisects
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3 years ago
(1 point) Linear System - Three Variables Solve the following system of equations using Gaussian elimination method. If there ar
EastWind [94]

Answer:

x=\frac{-363}{70} ≈ -5.1857

y=\frac{-192}{35} ≈ -5.4857

z=\frac{313}{84} ≈ 3.7262

Step-by-step explanation:

Rewrite the equation system as:

6x+8y=-75

-3x+6y+6z=5

2x-9y=39

Now, write the system in its augmented matrix form:

\left[\begin{array}{cccc}6&8&0&-75\\-3&6&6&5\\2&-9&0&39\end{array}\right]

applying row reduction process to  its associated augmented matrix:

Swap R1 and R3, and then Swap R1 and R2:

\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\6&8&0&-75\end{array}\right]

R3+2R1

\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\0&20&12&-65\end{array}\right]

3R2+2R1

\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&20&12&-65\end{array}\right]

15R3+20R2

\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&0&420&1565\end{array}\right]

Now we have a simplified system:

-3x+6y+6z=5\\0-15y+12z=127\\0+0+420z=1565

-3x+6y+6z=5\hspace{5 mm}(1)\\0-15y+12z=127\hspace{3 mm}(2)\\0+0+420z=1565\hspace{3 mm}(3)

From (3):

z=\frac{313}{84} (4)

Replacing (4) in (2)

y=\frac{-192}{35} (5)

Finally replacing (5) and (4) in (1)

x=\frac{-363}{70}

7 0
3 years ago
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