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jok3333 [9.3K]
3 years ago
10

You have a bag of chocolate candy. Ten of them are red, 7 are brown, 12 are green, and 9 are blue. What is the probability that

you pick a red candy, given that you have already picked a red candy and have not replaced it?
Mathematics
2 answers:
Brrunno [24]3 years ago
5 0

It would be \frac{10}{38}, or, in simplest form, \frac{5}{19}.

You get this by adding all the marbles to find the total number of marbles. <em>10+7+12+9</em>, which equals <em>38</em>.

You have <u>10 red marbles out of 38 total</u>, so that is represented by \frac{10}{38}!

Karo-lina-s [1.5K]3 years ago
3 0

9/37  is the correct answer.

                           


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Answer: The system of equation is,

2 ( x + y ) = 50

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Step-by-step explanation:

Let x represents the length of the rectangular brownie and y represents the width of the rectangular brownie.

Thus, the perimeter of the brownie = 2 ( x + y )

But, According to the question,

Perimeter of the brownie = 50,

2 ( x + y ) = 50

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Thus, the required system of equation is,

2 ( x + y ) = 50 , x = 2 y - 5


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A high school club has 10 members who are seniors and 8 members who
Taya2010 [7]

Answer:

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P(E⁻) = 1 - P(E)

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Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given A high school club has 10 members who are seniors and 8 members who  are juniors

n(S) = 10 + 8 = 18

If a member is randomly selected to be the club president

Let 'E' be the event that the person will  be a senior

The probability that the person will  be a senior

      P(E) = \frac{n(E)}{n(S)}

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The probability that the person will not  be a senior

P(E⁻) = 1 - P(E)

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