Answer:
Step-by-step explanation:
Given function is h(t) = -16t² + 1500
a). For h(t) = 1000 feet,
1000 = -16t² + 1500
1000 - 1500 = -16t² + 1500 - 1500
-500 = -16t²
t² = 
t = 
t = 5.59 sec
b). For h(t) = 940 feet,
940 = -16t² + 1500
940 - 1500 = -16t² + 1500 - 1500
-16t² = -560
t² = 
t = 
t = 5.92 sec
c). For domain and range of the function,
When the jumper comes down to the ground,
h = 0
0 =-16t² + 1500
t² = 
t = 
t = 9.68 sec
Since, x-values on the graph vary from x = 0 to x = 9.68,
Domain : [0, 9.68]
Vertex of the quadratic function: (0, 1500)
Since, coefficient of the highest degree term is negative, parabola will open downwards.
Therefore, y-values of the function will vary in the interval y = 0 to y = 1500
Range: [0, 1500]
7x + 9y = - 27_________eq1
3x - y = 3__________eq2
Multiply eq 2 by 9 and then add the resulting eq with eq1.
eq2 x 9 gives us 27x - 9y = 27___________eq3
add eq3 with eq1 we get.
34x = 0.
where x=0/34
x=0.
substitute x into any of the above equations to get y.
substitute x into eq1. we get:
7(0) + 9y =-27
9y = -27
y= -27/9
y = -3.
Given that the associative property of multiplication says that you can group the numbers in any combination, we can reorganize the expression as: 7·(10·3)=210. So the answer would be the first option.
Y would equal one bc negative two plus three is one