Let the integers be x and x + 2, provided x is even.
x(x + 2) = 360
x² + 2x = 360
x² + 2x - 360 = 0
(x - 18)(x + 20) = 0
x = 18, or x = -20
Thus, the integers are: 18 and 20, or -20 and -18
Answer:
(x-3)^2 + (y-1)^2 = 4
Step-by-step explanation:
The equation of a circle is usually written in the form
(x-h)^2 + (y-k)^2 = r^2
Where (h,k) is the center and r is the radius
The center is at the origin so (h,k) = (3,1) and the radius is 2 so r=2
(x-3)^2 + (y-1)^2 = 2^2
(x-3)^2 + (y-1)^2 = 4
Answer:
51 red
34 blue
#5 21
Step-by-step explanation:
3+2=5
85/5=17
2/3*17=51/34
top is red bottom blue
Y+4=-2(x+1)
This is the point slope form (y-y1) =m(x-x1)
I hope it will helped!
