Answer:
Step-by-step explanation:
One thousand, two hundred thirty seven ten thousandths
Answer:
Step-by-step explanation:
Based on the given conditions, formulate: 
Convert decimal to fraction:
Divide a fraction by multiplying its reciprocal:
Cross out the common factor: 
Calculate the product or quotient:
get the result:
Answer:
Answer:
either of two angles whose sum is 90°
The probability of the ball being white in the first basket is: 2/9
The probability of the ball being white in the second basket is: 3/13
Work:
First off, in basket 1, there are 9 balls in all, 2 of which are white, 7 of which are yellow. So, to find your denominator (If doing this in fraction form), you add up the number of balls. In this case, the first basket has 2 white balls and 7 yellows balls, so 2 + 7 = 9. To find your numerator (Which is the specified color ball probability), you just simply choose the number of balls it is asking for. In this question, it is asking for the probability of white balls in each basket. In basket one, there are 2 out of 11 balls in total. So, your answer would be that there are 2/11 white balls in basket 1.
I am not going to say this same process for the 2nd basket because it takes some time, but I hope this helps! :)
Answer:
1. 38, 80, 89 and 4. 14, 15, 29
I don't know if there is supposed to be only one, but both of those do not form right triangles.
Step-by-step explanation:
Evaluate all of them and see if they meet the requirements of the Pythagorean Theorem, a² + b² = c².
1. 38, 80, 89
a² + b² = c²
38² + 80² = 89²
1444 + 6400 = 7921
7844 ≠ 7921.
This is an answer because it doesn't satisfy the Pythagorean Theorem.
2. 16, 63, 65
a² + b² = c²
16² + 63² = 65²
256 + 3969 = 4225
4225 = 4225
This isn't the answer because it satisfies the Pythagorean Theorem.
3. 36, 77, 85
a² + b² = c²
36² + 77² = 85²
1296 + 5929 = 7225
7225 = 7225
This isn't the answer because it satisfies the Pythagorean Theorem.
4. 14, 15, 29
a² + b² = c²
14² + 15² = 29²
196 + 225 = 841
421 ≠ 841
This is an answer because it does not satisfy the Pythagorean Theorem.
