Answer: The first outcome shall be 0.33 or 33%.
The second outcome would be 0.5 or 50%
Step-by-step explanation: The bag contains exactly one yellow, one red and one green marble. So when he draws the first marble the sample space shall be the total possible outcomes, which is three, since he has three (3) marbles altogether. When he draws the first time without looking, all three marbles have an equal probability of being picked which can be derived thus;
P(Red) = Number of required possibilities/Number of all possibilities
P(Red) = 1/3
P(Red) = 0.33
Note that there is only one marble of each color which means P(Yellow) and P(Green) is also 0.33 respectively.
After choosing the first marble, without replacing the first one he now chooses another marble. The sample size would have reduced to 2 (since one marble has been drawn). Hence, the outcome when he draw a second marble can be calculated as follows;
P(Red) = Number of required outcomes/Number of possible outcomes
P(Red) = 1/2
P(Red) = 0.5
14.59
To solve, simply plug -7.1 into -Z. Since Z is negative in the equation, it will turn the Z that’s given to us into a negative. Since that Z is already negative, it will now become a positive since that’s what two negatives being multiplied make. This is what your problem will look like:
-(-7.1) + 7.49
7.1 + 7.49 = 14.59
