$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -4}}\quad ,&{{ 2}})\quad 
% (c,d)
&({{ 8}}\quad ,&{{ 5}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ 8}} -4}{2}\quad ,\quad \cfrac{{{ 5}} + {{ 2}}}{2} \right)$

8 0

3 years ago

Read 2 more answers

One zero of x3 – 3x2 – 6x + 8 = 0 is -2. What are the other zeros of the function?

hram777 [196]

Consider this solution, if it is possible, check the result:
1) if to divide polynomial 'x³-3x²-6x+8' on 'x+2' result is: x²-5x+4, then x³-3x²-6x+8=(x+2)(x²-5x+4);
2) x²-5x+4=(x-1)(x-4), then
3) x³-3x²-6x+8=(x+2)(x-1)(x-4).
4) zeros are: -2;1;4. Other zeros are: 1 and 4.
Answer: 1;4.

7 0

3 years ago

10^4/888x7<br> A.77.82<br> B78.50<br> C. 80<br> D.non of the above

labwork [276]

Answer is a hope it helps

6 0

3 years ago

What is the constant rate of change in given equation Y= -5x *please Hurry*

statuscvo [17]

Answer:

-5

Step-by-step explanation:

The x and the y are the factors of the equation. Simply extract the value that is not the variable, and, well, you’ll get your constant.

6 0

2 years ago