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3 years ago

When born, a baby weighed 8.5 pounds and gained 1.6 pounds per week for the first 10

Mathematics

1 answer:

ladessa [460]3 years ago

5 0

Answer:

I believe the answer is C

Step-by-step explanation:

if the baby weighted 8.5 pounds when born then that is the initial value therefore the baby will be weighted 1.6 times 10 weeks or w

hope this helps

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Jim can run a mile in 5 minutes and 50 seconds, john can run a mile in 6 minutes and 40 seconds.

QveST [7]

Jim's time is 5:50 and John's time is 6:40.

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2 years ago

In the figure below, AB is a diameter of circle P.

saw5 [17]

Answer:

317

Step-by-step explanation:

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2 years ago

3.) Which expression(s) are equivalent to 20?

Goryan [66]

Your choices of answers are not clear, is the letter x a variable or a multiplication?

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2 years ago

A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by ℎ = −16푡 ଶ+103푡+5 w

Liono4ka [1.6K]

Question:

A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by h(t)=-16t^2+80t+5, where t is measured in seconds. Write an equation to determine how long it will take for the ball to reach the ground.

Answer:

$t = 5.0625$

Step-by-step explanation:

Given

$h(t)=-16t^2+80t+5$

Required

Find t when the ball hits the ground

This implies that h(t) = 0

So, we have:

$0=-16t^2+80t+5$

Reorder

$-16t^2+80t+5 = 0$

Using quadratic formula, we have:

$t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}$

Where

$a = -16$ $b =80$ $c = 5$

So, we have:

$t = \frac{-80\±\sqrt{80^2 - 4*-16*5}}{2*-16}$

$t = \frac{-80\±\sqrt{6400 +320}}{-32}$

$t = \frac{-80\±\sqrt{6720}}{-32}$

$t = \frac{-80\±82.0}{-32}$

This gives:

$t = \frac{-80+82.0}{-32}$ or $t = \frac{-80-82.0}{-32}$

$t = \frac{2}{-32}$ or $t = \frac{-162}{-32}$

$t = -\frac{2}{32}$ or $t = \frac{162}{32}$

But time can not be negative.

So, we have:

$t = \frac{162}{32}$

$t = 5.0625$

<em>Hence, time to hit the ground is 5.0625 seconds</em>

3 0

2 years ago

Which equation represents the relationship between the x-and y-values shown in the table.

Dmitrij [34]

C. y = 3x - 4

Step-by-step explanation:

Given coordinates:

(2, 2), (3, 5), (5, 11), (7, 17)

The equation of any straight line is

y = mx + c

Where

m = Gradient

c = Constant

Gradient = y2 - y1/x2 - x1

Substitute any two values of y with the respective values of x.

Gradient = 17 - 2/7 - 2

= 15/5

= 3

Substitute the gradient into the general formula.

y = 3x + c

Substitute any value of the coordinate to the equation

2 = 3(2) + c

2 = 6 + c

c = -4

From y = mx + c,

substitute the values of m, the gradient, and c, the constant.

y = (3)x + (-4)

y = 3x - 4

5 0

2 years ago