What are the zeros of f(x) = x2 – 8x + 16?
2 answers:
It would be
Answer: the zeroes are at
x = 4
Explanation:
Factor it out:
ask yourself: what factors multiply to
16 and add up to − 8
thus
f(x) = (-4)(x - 4) x - 4 = 0
X = 4
<span>x^2 – 8x + 16 = 0
(x - 4)^2 = 0
x - 4 = 0
x = 4
hope it helps</span>
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