3 years ago

What are the zeros of f(x) = x2 – 8x + 16?

2 answers:

8 0

It would be
Answer: the zeroes are at
x = 4
Explanation:
Factor it out:
ask yourself: what factors multiply to
16 and add up to − 8

thus
f(x) = (-4)(x - 4) x - 4 = 0

X = 4

rusak2 [61]3 years ago

3 0

x^2 – 8x + 16 = 0
(x - 4)^2 = 0
x - 4 = 0
x = 4

hope it helps

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