Answer:
D.
Step-by-step explanation:
Answer:
the length of RS to the nearest tenth of a foot is 240.6ft
7/8-3/8=
Is it more than one half or less then one half


When

, you're left with

When

or

, you're left with

Adding the two equations together gives

, or

. Subtracting them gives

,

.
Now, you have



By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that

and

. These alone tell you that you must have

and

.
So the partial fraction decomposition is
The correct answer is 104 games.
You get that number by dividing 160 with a 100, to find out how large 1% is, and then you multiply it with 65 to find out how much 65% is, and the answer is 104 games.