Which is the decimal equivalent of 2/3 A. 0.23 OB. 0.32 O c. 0.3 O D. 0.6

liberstina [14]

Micheal has 40ft of fencing for the rectangular dog run. So the perimeter of the dog run is 40ft.

Perimeter=40ft

The perimeter of a rectangle is:

P=2l+2w

Since we know the length is 5 and the perimeter is 40, we can solve for the width.

P=2l+2w
40=2*(5)+2w
40=10+2w
subtract 10 from both sides
30=2w
divide both sides by 2
15=w

The width of the fence is 15feet.

3 0

3 years ago

A piece of steel pipe 12.5 feet long weighs 158 pounds. How much does a piece of the same steel pipe 18.75 feet long weigh?

jonny [76]

Answer:

18.75 feet of steel pipe weighs 237 pounds

explanation:

find out how much 1 feet weighs than u can find out how much 18.75 feet.

by doing it like this

158÷ 12.5

=12.64

1 feet equals 12.64 pounds

12.64× 18.75

=237 pounds this is the answer

i do apologize if it wrong

8 0

3 years ago

Read 2 more answers

A is an m×n matrix.Check the true statements below:A. The kernel of a linear transformation is a vector space.B. If the equation

Bess [88]

Answer:

Results are (1) True. (2) False. (3) False. (4) True. (5) True. (6) True.

Step-by-step explanation:

Given A is an $m\times n$ matrix. Let $T :U\to V$ be the corresponding linear transformationover the field F and $\theta$ be identity vector in V. Now if $x\in Ker( T)\implies T(x)=\theta$ .

(1) The kernel of a linear transformation is a vector space : True.

Let $x,y\in Ker( T)$ , then,

$T(x+y)=T(x)+T(y)=\theta+\theta=\theta\impies x+y\in Ker( T)$

hence the kernel is closed under addition.

Let $\lambda\in F, x\in Ker( T)$ , then

$T(\lambda x)=\lambda T(x)=\lambda\times \theta=\theta$

$\lambda x\in Ker(T)$ and thus Ket(T) is closed under multiplication

Finally, fore all vectors $u\in U$ ,

$T(\theta)=T(\theta+(-\theta))=T(\theta)+T(-\theta)=T(\theta)-T(\theta)=\theta$

$\implies \theta\in Ker(T)$

Thus Ker(T) is a subspace.

(2) If the equation Ax=b is consistent, then Col(A) is $\mathbb R^m$ : False

if the equation Ax=b is consistent, then Col(A) must be consistent for all b.

(3) The null space of an mxn matrix is in $\mathbb R^m$

: False

The null space that is dimension of solution space of an m x n matrix is always in $\mathbb R^n$ .

(4) The column space of A is the range of the mapping $x\to Ax$

: True.

(5) Col(A) is the set of all vectors that can be written as Ax for some x. : True.

Here Ax will give a linear combination of column of A as a weights of x.

(6) The null space of A is the solution set of the equation Ax=0.

: True

5 0

3 years ago

- How do I solve this,I do not know how to start it

Ulleksa [173]

Answer:

what do you mean?

Step-by-step explanation:

5 0

3 years ago

In November, the price of a GizmoPhone was double the price in March. In December, the price was $57, which was $29 less than th

Jet001 [13]

December = $57

In December, the price was $57, which was $29 less than the price in November then November price was: $57 + $29 = $86
In November, the price of a GizmoPhone was double the price in March. so March: $86 x 2 = $172

answer: the price of a GizmoPhone in March was $172

7 0

3 years ago