T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120
Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10
Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)
0 = 3t - 2
2 = 3t
2/3 = t
Plug 2/3 into original equation, this is a maximum. We want the minimum:
0 = t - 5
5 = t
Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
Step-by-step explanation:
Given

Hope it will help :)
Answer:
Function B has a greater rate of change
Step-by-step explanation:
to find the rate of change or slope
Function A
(0,2) (3,5)
m =(y2-y1)/(x2-x1)
= (5-2)/(3-0)
= 3/3
m=1
Function B
m =(y2-y1)/(x2-x1)
= (9-6)/(6-4)
= 3/2
= 1.5
Function B has a greater rate of change
Answer:
3 • (2x - 7) - (x + 4) = 0
then do 3.1 Pull out like factors :
5x - 25 = 5 • (x - 5)
5 • (x - 5) = 0
4.2 Solve : x-5 = 0
Add 5 to both sides of the equation :
x = 5
Step-by-step explanation:
Answer:
3. $600,000
Step-by-step explanation:
We have been given that a tenant rented a store to use as a real estate school at a base rent of $1,500 a month. Additionally, the tenant agreed to pay 3% of gross annual sales over $200,000.
Let us find base annual rent.

Let us find the amount of rent paid as 3% of gross annual sales.

Let us find amount of sales over $200,000 by dividing $12000 by 3% or 0.03.

Total sales would be $400,000 plus $200,000.

Therefore, the total sales for that year was $600,000 and 3rd option is the correct choice.