Answer:
D:Spring A is 3 m longer than spring B because 15 – 12 = 3.
Step-by-step explanation:
In this question, you should remember the Hooke's Law in physics.
The Hooke's Law simply explains that the extension that occurs on a spring is directly proportional to the load applied on it.
The mathematical expression for this law is
![F=-kx](https://tex.z-dn.net/?f=F%3D-kx)
where;
F= force applied on the spring
x = the extension on the spring
k= the spring constant which varies in spring.
The question will need you to calculate the extension on the springs A and B then compare the values obtained.
<u>In spring A</u>
Force, F=60N and spring constant ,k=4 N/m
To find the extension x apply the expression;
![F=-kx\\\\60=-4*x\\\\60=-4x\\\\\frac{60}{-4} =\frac{-4x}{-4} \\\\\\-15=x](https://tex.z-dn.net/?f=F%3D-kx%5C%5C%5C%5C60%3D-4%2Ax%5C%5C%5C%5C60%3D-4x%5C%5C%5C%5C%5Cfrac%7B60%7D%7B-4%7D%20%3D%5Cfrac%7B-4x%7D%7B-4%7D%20%5C%5C%5C%5C%5C%5C-15%3Dx)
Here the spring extension is 15 m
<u>In spring B</u>
Force, F=60N and spring constant , k=5N/m
To find the extension x apply the same expression
![F=-kx\\\\60=-5*x\\\\60=-5x\\\\\\\frac{60}{-5} =\frac{-5x}{-5} \\\\\\-12=x](https://tex.z-dn.net/?f=F%3D-kx%5C%5C%5C%5C60%3D-5%2Ax%5C%5C%5C%5C60%3D-5x%5C%5C%5C%5C%5C%5C%5Cfrac%7B60%7D%7B-5%7D%20%3D%5Cfrac%7B-5x%7D%7B-5%7D%20%5C%5C%5C%5C%5C%5C-12%3Dx)
Here the extension on the spring is 12 m
<u>Compare</u>
The extension on spring A is 3 m longer than that in spring B because when you subtract the value of spring B from that in spring A you get 3m
![=15m-12m=3m](https://tex.z-dn.net/?f=%3D15m-12m%3D3m)