2) write a linear function that passes through point ( 3, 6) and is perpendicular to Y=2X-1.

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

3 0

Answer:

y=-1/2*+5

Step-by-step explanation:

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General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Identify

Point (-1, -8)

Point (-4, -4)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formula]: $\displaystyle d = \sqrt{(-4--1)^2+(-4--8)^2}$
[√Radical] (Parenthesis) Subtract: $\displaystyle d = \sqrt{(-3)^2+(4)^2}$
[√Radical] Evaluate exponents: $\displaystyle d = \sqrt{9+16}$
[√Radical] Add: $\displaystyle d = \sqrt{25}$
[√Radical] Evaluate: $\displaystyle d = 5$