3,9,15 what is the 36th term
1 answer:
firstly, we have to find the difference
the diff is 6
we apply the concept diN+0
Di is difference
N is n
0 is first term - difference
first term is 3
diff is 6
3-6 = -3
nth term is 6n-3
then, we just substitute which is n is the 36th term
: 6(36)-3 = 213
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