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3 years ago

Which keystone species feed on other animals and prevent them from damaging the ecosystem?.

Chemistry

1 answer:

DochEvi [55]3 years ago

7 0

Predators feed on other animals and keep the ecosystem in balance

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For the reaction 2 NH 3 ( g ) − ⇀ ↽ − 3 H 2 ( g ) + N 2 ( g ) 2NH3(g)↽−−⇀ 3H2(g)+N2(g) the equilibrium concentrations were found

Alex787 [66]

Answer:

Equilibrium constant is: 1.09

Explanation:

The proposed equilibrium is:

2NH₃(g) ⇄ 3H₂(g)+N₂(g)

Concentrations are: [NH₃] = 0.250 M; [H₂] = 0.440 M; [N₂] = 0.800 M

Expression for Kc is: [H₂]³ . [N₂] / [NH₃]²

We replace data → Kc = (0.440³ . 0.800) / 0.250²

Kc = 1.09

Remember that equilibrium constant has no units and it depends on T°

6 0

3 years ago

Read 2 more answers

What is everything around us made up of

disa [49]

Answer:

atoms

have a nice day!

5 0

3 years ago

Read 2 more answers

The liquid in a graduated cylinder has a volume of 70 mL. You put a small solid ball into the cylinder, and the height of the li

Travka [436]

Answer:

10 mL

Explanation:

4 0

3 years ago

Mang Kadyo has just bought a piece of land in province.The place is situated near a mountain with a lagoon on the southern part

nadya68 [22]

Answer:

a.In the garden

Explanation:

Because, inside from garden with big tub like a stock tank on your patio. They grow tubers planted in pots beneath the water and send up stems with rounded leaves and star-shaped blossoms that float on the surface.

I hope it helps to us. Always welcome my youngest sister:). keep learning and God bless.

6 0

3 years ago

Under certain conditions the rate of this reaction is zero order in dinitrogen monoxide with a rate constant of ·0.0080Ms−1: 2N2

weqwewe [10]

Answer:

$t=1.875s$

Explanation:

Hello,

In this case, for the given reaction, the concentration of dinitrogen oxide is quantified as:

$\frac{dC_{N_2O}}{dt}=r_{N_2O}$

Considering that in molar units (M), the initial and final concentration of dinitrogen oxide are:

$C_{N_2O,initial}=\frac{150.0mmol}{5.0L}*\frac{1mol}{1000mmol} =0.03M\\\\C_{N_2O,final}=\frac{75.0mmol}{5.0L}*\frac{1mol}{1000mmol} =0.015M$

Now, since the rate is zeroth order in dinitrogen oxide, it depends on the rate constant only:

$\frac{dC_{N_2O}}{dt}=-k$

Thus, by integrating from the initial concentration to the final concentration:

$\int\limits^{0.015M}_{0.03M} {dC_{N_2O}} \, dx =-k\int\limits^t_0 {} \, dt$

The time finally results:

$t=\frac{0.015M-0.03M}{-0.0080M/s} \\\\t=1.875s$

Best regards.

8 0

3 years ago