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MrRa [10]
3 years ago
9

Which type of decay does not involve the decaying atom's atomic number to change?

Chemistry
1 answer:
Reika [66]3 years ago
6 0

Answer:

c-gamma decay

Explanation:

In gamma decay, neither the atomic number or the mass number is changed

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Four physical properties of 500g of butter
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 A piece of paper is thin, slightly smooth, can be white and smell woody. 500 g of butter has a density of 0.911 g/ml and has a volume thus of 548.85 ml. 
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You titrate 41.27 mL of 0.108 M Ca(OH)2 into 25.00 mL of citric acid (C6H307) (triprotic). What is the balanced equation and the
Triss [41]

Answer:

3Ca(OH)2 + 2C6H8O7 → 6H2O + Ca3(C6H5O7)2

And 0.119M is the concentration of the citric acid.

Explanation:

In an acid-base reaction, the proton H+ and the hydroxil ion OH- reacts producing water. The ions of the acid and base (C6H5O7³⁻ and Ca²⁺ ions produce the respective salt) as follows:

Ca(OH)2 + C6H8O7 → H2O + Ca3(C6H5O7)2

To balance the Calcium ions:

3Ca(OH)2 + C6H8O7 → H2O + Ca3(C6H5O7)2

To balance the C6H5O7³⁻ ions:

3Ca(OH)2 + 2C6H8O7 → H2O + Ca3(C6H5O7)2

And to balance the oxygens of water:

3Ca(OH)2 + 2C6H8O7 → 6H2O + Ca3(C6H5O7)2

And this is the balanced reaction.

The moles of Ca(OH)2 that reacts are:

41.27mL = 0.04127L * (0.108mol/L) = 0.004457 moles Ca(OH)2

<em>Moles of citric acid:</em>

0.004457 moles Ca(OH)2 * (2mol C6H8O7 / 3mol Ca(OH)2) = 0.002971 moles C6H8O7

In 25.00mL = 0.02500L:

0.002971 moles C6H8O7 / 0.0250L =

<h3>0.119M</h3>

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3 years ago
What is the relationship between the strength of the magnetic field and the deflection of the galvanometer needle?
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Similarly, if magnet is held stationary and the coil is moved away and towards the magnet, the galvanometer shows deflection in similar manner. It is also seen that, the faster the change in the magnetic field, the greater will be the induced emf or voltage in the coil.

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2 years ago
Which is the correct electron dot diagram for krypton (Kr)?
SCORPION-xisa [38]
Krypton is in group 18, and so it has 8 valence electrons. B is the answer
4 0
4 years ago
Liquid butane, C4H10, is stored in cylinders to be used
Ganezh [65]

Answer:

  • <u>13.0kJ</u>

Explanation:

The<em> heat</em> to <em>vaporize</em> a l<em>iquid</em> is equal to the amount of liquid in moles multiplied by the specific <em>heat of vaporiztion</em> per mole.

First, calculate the number of moles in 35.5g of <em>butane</em>.

  • Molar mass of butane: 58.124 g/mol

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Now, calculate the heat to vaporize that amount of <em>liquid butane</em>:

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  • Heat = 0.6107632mol × 21.3kJ/mol = 13.0 kJ

The answer must be reported with 3 significant figures.

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