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MrRa [10]
3 years ago
9

Which type of decay does not involve the decaying atom's atomic number to change?

Chemistry
1 answer:
Reika [66]3 years ago
6 0

Answer:

c-gamma decay

Explanation:

In gamma decay, neither the atomic number or the mass number is changed

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Alcohol or acid will travel the furthest up the paper chromatography? pls help thanks and explain
d1i1m1o1n [39]

Answer:

True

Explanation:

Yes.

The distance that the molecules move depends on their solubility in the solvent and the size of the molecules. Heavy molecules will travel slower and therefore travel a shorter distance in the time the chromatography is run.

We know from such things as felt tip pens that colourings can be soluble in different solvents. Water soluble felt pens have colours that are - well - water soluble. Permanent felt pens have colours that are insoluble in water but that are soluble in another solvent. This could well be alcohol.

The water soluble colours may also be soluble in alcohol. The solubility in alcohol will be different from the solubility in alcohol, and so the Rf value ( the distance travelled) will also be different.

Because of the complicated shapes of the colours, the colours may not have the same order in the Rf values in the different solvents.

4 0
2 years ago
How do I balance this chemical reaction ?
Assoli18 [71]
Ignore my writing answer is in pictute

8 0
2 years ago
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svlad2 [7]
The 2nd one is the right answer

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3 0
2 years ago
A 25.0-mL sample containing Cu2+ gave an instrument signal of 25.2 units (corrected for a blank). When exactly 0.500 mL of 0.027
irga5000 [103]

Answer:

The molar concentration of Cu²⁺ in the initial solution is 6.964x10⁻⁴ M.

Explanation:

The first step to solving this problem is calculating the number of moles of Cu(NO₃)₂ added to the solution:

C = \frac{n}{V} \\0.0275 = \frac{n}{0.0005} \\

n = 1.375x10⁻⁵ mol

The second step is relating the number of moles to the signal. We know the the n calculated before is equivalent to a signal increase of 19.9 units (45.1-25.2):

1.375x10⁻⁵ mol _________ 19.9 units

        x              _________  25.2 units

x = 1.741x10⁻⁵mol

Finally, we can calculate the Cu²⁺ concentration :

C = 1.741x10⁻⁵mol / 0.025 L

C = 6.964x10⁻⁴ M

7 0
3 years ago
Ill give u brainliest and all my points! pls help
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http://www.atnf.csiro.au/outreach/education/senior/cosmicengine/stars_hrdiagram.html. This will give u the answer, just go to link

6 0
3 years ago
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