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Marat540 [252]
3 years ago
14

8 meters increased by 25% is

Mathematics
2 answers:
Kobotan [32]3 years ago
5 0
10 meters, because 25 percent of 8 is 2, 2 plus 8 is 10.
PtichkaEL [24]3 years ago
5 0
10m meters hope this helped you out
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Divide (-2x-3+8x^2) by (1+4x)
nataly862011 [7]

Answer:

A

Step-by-step explanation:

I'm going to show you a little secret. It's called symbolab.com. You can solve almost any algebraic problem. It also gives a step by step explanation

6 0
3 years ago
If f(x) is a third degree polynomial function and g(x) = f(–2x), which of the following is NOT true?
valina [46]

Answer:

f(x) and g(x) have the same x-intercepts (is <em>not true</em>)

Step-by-step explanation:

g(x) is a reflection across the y-axis and a horizontal compression of f(x). In general those transformations will move the x-intercepts. (The y-intercept and the number of x-intercepts will remain unchanged.)

_____

<em>Comment on the question/answer</em>

f(x) = x^3 is a 3rd degree polynomial. When transformed to g(x) = -8x^2, its only x-intercept (x=0) remains the same. The answer above will not apply in any instance where the only x-intercept is on the line of reflection. (The question is flawed in that it does not make any exception for such functions.)

8 0
3 years ago
How to write repeating decimals as fractions
nignag [31]

Answer:

You take the repeating group of digits and divide it by the same number of digits but formed only by 9s.

Step-by-step explanation:

Let's say you have 0.111111111111...., your repeating pattern is 1, that consists of one digit (1).  You take that digit and you divide it by 9:

1/9 is the fraction equivalent to 0.111111111111111...

Let's say you have 0.12121212121212...., the repeating pattern is 12, that consists of 2 digits (12).  You take those 2 digits and divide them by 99:

12/99 is the fraction equivalent to 0.12121212121212...

which can be reduced to 4/33

If you have 0.363363363363..., your repeating pattern is 363, which is 3 digits, so you divide 363by 999:

363/999 is the fraction equivalent to  0.363363363363...

which can be simplified to 121/333

7 0
3 years ago
How can you get equation b from equation A. 3(x+2)=18 B. X+2=18
Rzqust [24]

Answer:

We start with the equation:

A: 3*(x + 2) = 18

And we want to construct equation B:

B: X + 2 = 18

where I suppose that X is different than x.

Because in both equations the right side is the same thing, then the left side also should be the same thing, this means that:

3*(x + 2) = X + 2

Now we can isolate the variable x.

(x + 2) = (X + 2)/3

x = (X + 2)/3 - 2

Then we need to replace x by  (X + 2)/3 - 2 in equation A, and we will get equation B.

Let's do it:

A: 3*(x + 2) = 18

Now we can replace x by =  (X + 2)/3 - 2

3*( (X + 2)/3 - 2 + 2) = 18

3*(  (X + 2)/3 ) = 18

3*(X + 2)/3 = 18

(X + 2) = 18

Which is equation B.

3 0
2 years ago
A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect
Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99

Compute the probability that a person does not have the disease as follows:

P(D^{c})=1-P(D)=1-0.88=0.12

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188

Compute the probability that a randomly selected person is tested negative  as follows:

P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})

           =0.0264+0.1188\\=0.1452

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0
3 years ago
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