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marshall27 [118]
2 years ago
15

6(1 - 6x) < 38 - 4x What is the answer to this equation.

Mathematics
2 answers:
sergij07 [2.7K]2 years ago
6 0

Answer:

x>-1

Step-by-step explanation:

vesna_86 [32]2 years ago
6 0

Answer:

x > -1

Step-by-step explanation:

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25^9+5^17 is divisible by 30.
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1.5 x 10↑11

Hopefully that helps.

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Jennifer makes 45 blueberry muffins using 6 cups of flour. What is the ratio of cups of flour to blueberry muffins?\
likoan [24]

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6:45

Step-by-step explanation:

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2 years ago
Simplify 5(x + 3) - 9x+4.<br>O A. 14x+7<br>O B.-4x+19<br>O C. 14x+19<br>D. -4x+7​
Julli [10]

Answer:

B

Step-by-step explanation:

distribute

5x+15-9x+4

combine like terms

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8 0
3 years ago
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Select the correct answer. If a six-sided die is rolled 30 times, how many times can you expect to get a 6?​
solniwko [45]

Answer:

5

Step-by-step explanation:

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6 0
3 years ago
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The mayor is interested in finding a 98% confidence interval for the mean number of pounds of trash per person per week that is
saul85 [17]

Solution :

Given :

Sample mean, $\overline X = 34.2$

Sample size, n = 129

Sample standard deviation, s = 8.2

a. Since the population standard deviation is unknown, therefore, we use the t-distribution.

b. Now for 95% confidence level,

   α = 0.05, α/2 = 0.025

  From the t tables, T.INV.2T(α, degree of freedom), we find the t value as

  t =T.INV.2T(0.05, 128) = 2.34

  Taking the positive value of t, we get  

  Confidence interval is ,

  $\overline X \pm t \times \frac{s}{\sqrt n}$

 $34.2 \pm 2.34 \times \frac{8.2}{\sqrt {129}}$

 (32.52, 35.8)

 95% confidence interval is  (32.52, 35.8)

So with $95 \%$ confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.

c. About $95 \%$ of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about $5 \%$ that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.  

4 0
2 years ago
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