In a triangle ABC with |AB|=9m,|AC| =6m ,the sides AB and AC are produced to points X and Y respectively such that angleBXY=62°,
and angle AYX=51°, calculate |BC| ..please help Mee♀️♀️
1 answer:
Answer:
|BC| = 9.4 m
Step-by-step explanation:
Angle bxy = angle abc (reason, corresponding angles)
Angle ayx = angle acb ( reason , corresponding angles)
So angle abc= 62°
Angle acb = 51°
Angle acb + and + bac = 180 (reason, sum of angles in a triangle)
Anlge bac = 180-62-51
Angle bac= 180-113
Angle back = 67°
Using sine formula
|BC| /sin 67 = 9/sin 62
|BC| = sin 67 *9/sin62
|BC| = 9.4 m
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