Question

In a triangle ABC with |AB|=9m,|AC| =6m ,the sides AB and AC are produced to points X and Y respectively such that angleBXY=62°,and angle AYX=51°, calculate |BC| ..please help Mee‍♀️‍♀️​

Answer 1

Answer:

|BC| = 9.4 m

Step-by-step explanation:

Angle bxy = angle abc (reason, corresponding angles)

Angle ayx = angle acb ( reason , corresponding angles)

So angle abc= 62°

Angle acb = 51°

Angle acb + and + bac = 180 (reason, sum of angles in a triangle)

Anlge bac = 180-62-51

Angle bac= 180-113

Angle back = 67°

Using sine formula

|BC| /sin 67 = 9/sin 62

|BC| = sin 67 *9/sin62

|BC| = 9.4 m