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2 years ago

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I need the answer hurry please

1 answer:

denis23 [38]2 years ago

3 0

For all of the questions or only one-?

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A triangle has sides with lengths of 7 feet, 15 feet, and 17 feet. is it a right triangle?

aksik [14]

To test if this is a right triangle, let's test these side lengths with the Pythagorean Theorem.

a^2 + b^2 = c^2

c is the hypotenuse, the longest side of a right triangle.
a and b are the legs of the right triangle.

a = 7
b = 15
c = 17

7^2 + 15^2 = 17^2 ?

49 + 225 = 289 ?

274 ≠ 289

Thus, this triangle is not a right triangle since it does not satisfy the Pythagorean Theorem.

Have an awesome day! :)

8 0

3 years ago

What is 5x10-5x6 thank you

NemiM [27]

The answer is 20.
5*10-5*6=50-30=20

5 0

3 years ago

Read 2 more answers

What are the solution(s) to the quadratic equation 50 - x² = 0?

grandymaker [24]

Answer:

The answer is C.

Step-by-step explanation:

$50-x^2=0$

$x^2=50$

$x=\pm \sqrt{50} =\pm \sqrt{25*2}=\pm 5\sqrt{2}$

The answer is C (I am assuming that it isn't 5/2).

7 0

3 years ago

PQR is a right angled triangle calculate the size of angle marked x

romanna [79]

Answer:

$\displaystyle x \approx 37.4^\circ$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality<u> </u>

<u>Trigonometry</u>

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] cosθ = adjacent over hypotenuse<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

Angle θ = <em>x</em>

Adjacent Leg = 5.8

Hypotenuse = 7.3

<u>Step 2: Solve for </u><em><u>x</u></em>

Substitute in variables [Cosine]: $\displaystyle cosx^\circ = \frac{5.8}{7.3}$
[Fraction] Divide: $\displaystyle cosx^\circ = 0.794521$
[Equality Property] Trig inverse: $\displaystyle x^\circ = cos^{-1}(0.794521)$
Evaluate trig inverse: $\displaystyle x = 37.39^\circ$
Round: $\displaystyle x \approx 37.4^\circ$

8 0

3 years ago

N= 7/3T+17 <br> Solve the equation for T

LenaWriter [7]

7/3T=N-17
T=3/7(N-17)
T=3/7N -51/7

5 0

3 years ago