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1 answer:
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To find the number of terms in the arithmetic sequence, we need to use the formula
where
is the nth number, 
is the first number, n is the number of terms and d is the difference of the two consecutive numbers.
7373 = 1313 + (n - 1)(303)
7373 = 1313 + 303n - 303
7373 = 1010 + 303n
7373 - 1010 = 303n
6363 = 303n
6363 ÷ 303 = n
n = 21
Therefore, there are 21 terms in the arithmetic sequence given.
where
7373 = 1313 + (n - 1)(303)
7373 = 1313 + 303n - 303
7373 = 1010 + 303n
7373 - 1010 = 303n
6363 = 303n
6363 ÷ 303 = n
n = 21
Therefore, there are 21 terms in the arithmetic sequence given.
Answer:
The amount invested in gold bullion by Mr. Eliot = $50,000
Step-by-step explanation:
Total amount of savings Me. Eliot ha s = $150,000
Let us assume the amount invested in gold bullion = $m
So, the amount invested in bank = $150,000 - m
Now, 5% on m =
So, the profit in gold bullion = 0.05 m
and 3% on (150,000 -m) =
= 4,500 - 0.03 m
So, the profit in bank = 4,500 - 0.03 m
Now, the total profit = $5,500
⇒Profit from gold bullion + ban = $5,500
⇒0.05 m + 4,500 - 0.03 m = $5,500
or, 0.02 m = 1000
⇒ m = 1000/0.02 = 50,000
Hence, the amount invested in gold bullion = m = $50,000