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STatiana [176]
3 years ago
13

What is the total cost for an item that costs 26.50 and has a sales tax rate of 6%

Mathematics
1 answer:
Zarrin [17]3 years ago
3 0
$27.83 I'm pretty sure.
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17. You bought four cans of chicken noodle soup at the grocery store. You paid a total of 3.10
Brrunno [24]

Answer:

0.775

Step-by-step explanation:

Divide 3.10 by the number of cans you have. The total number of cans you have is 4. So divide 3.10 by 4 and you will have the answer of 0.775.

4 0
3 years ago
Read 2 more answers
I need help with this
m_a_m_a [10]
Nearest 100: 543,800
Nearest 1,000: 544,800
Nearest 10,000: 540,800

6 0
3 years ago
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Which statement must be true about line TU?
just olya [345]
Line tu is parallel to rs
5 0
3 years ago
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What is the equation of the line that passes through (-3,-1 ) and has a slope of 3/5
vfiekz [6]

The point-slope form:

y-y_1=m(x-x_1)

We have the point (-3, -1) and the slope m = 3/5. Substitute:

y-(-1)=\dfrac{3}{5}(x-(-3))\\\\y+1=\dfrac{3}{5}(x+3)\qquad\text{use distributive property}\\\\y+1=\dfrac{3}{5}x+\dfrac{9}{5}\qqua\text{subtract 1 from both sides}\\\\y=\dfrac{3}{5}x+\dfrac{4}{5}\qquad\text{multiply both sides by 5}\\\\5y=3x+4\qquad\text{subtract 3x from both sides}\\\\-3x+5y=4\qquad\text{change the signs}\\\\3x-5y=-4

Answer:

point-slope form: y + 1 = 3/5(x + 3)

slope-intercept form: y = 3/5x + 4/5

standard form: 3x - 5y = -4

7 0
3 years ago
A particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams. The heavies
RoseWind [281]

Answer:

The heaviest 5% of fruits weigh more than 747.81 grams.

Step-by-step explanation:

We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.

Let X = <u><em>weights of the fruits</em></u>

The z-score probability distribution for the normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean weight = 733 grams

            \sigma = standard deviation = 9 grams

Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;

                    P(X > x) = 0.05       {where x is the required weight}

                    P( \frac{X-\mu}{\sigma} > \frac{x-733}{9} ) = 0.05

                    P(Z > \frac{x-733}{9} ) = 0.05

In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;

                               \frac{x-733}{9}=1.645

                              {x-733}}=1.645\times 9

                              x = 733 + 14.81

                              x = 747.81 grams

Hence, the heaviest 5% of fruits weigh more than 747.81 grams.

8 0
3 years ago
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