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PIT_PIT [208]
3 years ago
9

In the program below, which variable has the same scope as strA?

Computers and Technology
2 answers:
xz_007 [3.2K]3 years ago
7 0

Answer:

i dont under stand it ........

Natalka [10]3 years ago
7 0

First, we have to understand what scope is. When variables are declared, they are only available in the code block they're declared in, unless they're global variables (this doesn't apply here).

strFirst is declared in usernameMaker and that is the only place it is available in.

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Which relation is created with the primary key associated with the relationship or associative entity, plus any non-key attribut
konstantin123 [22]

Answer:

- Transform binary or unary M:N relationship or associative entity with its own key.

Explanation:

Transform binary relation is described as the method through which a decimal can easily be converted into binary while the unary relationship is described as a relationship in which both the two participants occurs from the same entity.

In the given case, 'transform binary or unary M:N relationship' can be created using 'the primary key linked with the relationship plus any non-key aspects of the relationship and the primary keys of the related entities' as it displays the existence of a relationship between the occurrences of a similar set of the entity i.e. associative entity here.

5 0
4 years ago
Ns.office.com/Pages/ResponsePage.aspx?id=bd8
bulgar [2K]

Answer:

spreadsheet software

Explanation:

Spreadsheet software is an application that allows users to organize data in columns and rows and perform calculations on the data. These columns and rows collectively are called a worksheet.

6 0
3 years ago
Read 2 more answers
Write a C program that creates two threads to run the Fibonacci and the Runner processes. Threads will indicate the start and th
OleMash [197]

Answer:

see explaination

Explanation:

#include <pthread.h>

#include <stdio.h>

int sumOfN = 0;

int arr[1000];

int n;

void * findSumOfN(void *a){

printf("Thread 1 Starting\n");

sumOfN = (n * (n+1)) / 2; //finds sum of first n natural numbers

printf("Thread 1 Finished\n");

pthread_exit(0);

}

void * fibonacci(void *a){

printf("Thread 2 Starting\n");

arr[0]=0;

arr[1]=1;

for(int i=2;i<n;i++) //find fibonacci numbers iteratively

arr[i]=arr[i-1]+arr[i-2];

printf("Thread 2 Finished\n");

pthread_exit(0);

}

int main(void){

printf("Please enter the value of n \n");

scanf("%d", &n);

if (n <= 0)

{

printf("Wrong input ! \n"); //input validation

return 0;

}

pthread_t thread1, thread2;

pthread_create(&thread1,NULL, findSumOfN, NULL); //Create threads

pthread_create(&thread2,NULL, fibonacci, NULL);

pthread_join(thread1,NULL); //Start threads

pthread_join(thread2, NULL);

printf("The sum of first %d numbers is : %d \n",n, sumOfN);

printf("The first %d fibonacci numbers are : \n",n);

for (int i = 0; i < n; ++i)

{

printf("%d ", arr[i]);

}

printf("\n");

return(0);

}

3 0
4 years ago
Which argument forces a writer to return to and change the input before resolving a “UnicodeError”?
garri49 [273]

Answer:

B

Explanation:

3 0
4 years ago
You want to set the sticky bit on an existing directory, subdir, without otherwise altering its permissions. to do so, you shoul
nikklg [1K]

If you want to set the sticky bit on an existing directory, subdir, without otherwise altering its permissions. to do so, you should type chmod a <u>t  <subdir>.</u>

<h3>What is Subdir?</h3>

The Definition of the term subdirectory is known to be a kind of an organizational directory that can be seen on a computer.

It is known to be one that can be found inside another directory  such as a subfolder. It is seen as the file a person is looking for and it is one that needs to have an extension.

Therefore, if you want to set the sticky bit on an existing directory, subdir, without otherwise altering its permissions. to do so, you should type chmod a <u>t  <subdir>.</u>

Learn more about directory from

brainly.com/question/14845522

#SPJ1

See full question below

You want to set the sticky bit on an existing directory, subdir, without otherwise altering its permissions. To do so, you should type:

chmod a+_____ <subdir>

- s

- p

- b

- t

6 0
2 years ago
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