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3 years ago

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In what ways was the first Mac OS different from the operating systems used by most early PCs? Users clicked on pictures to laun

ch applications. It provided multitasking capabilities. Users didn't have to memorize lots of commands. Different applications used similar interfaces. It had a colorful display.

Computers and Technology

1 answer:

777dan777 [17]3 years ago

3 0

Users didn't have to memorize lots of commands.

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A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

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3 years ago

Choose the appropriate software category for each specific application shown.

Tom [10]

Python is the correct answer

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2 years ago

A network technician is setting up a wireless access point in the front office of a small company. The technician needs to disab

VladimirAG [237]

Answer:

He should disable UPnP technology to disallow devices to dynamically add themselves to the network without configuration.

Explanation:

UPnP stands for Universal Plug n Play.
It is an easiest way that allows gadgets to find all other devices connecting to your network.
This can also modify router settings to allow devices from outside the network to access the router.
External IP address can also be obtained by the gadget and a new port forwarding map can be set
So from all perspectives, UPnP is an open invitation for hackers to scan for the ports and hack into the device.
UPnP is a vulnerability to the secure system

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3 years ago

True or False: Nested elements must be indented with respect to parent elements in

Dovator [93]

Answer:

true

Explanation:

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3 years ago

You can use these finger motions to perform specific functions on a Mac OS system:

notka56 [123]

Answer:

Gestures

Explanation:

Gestures is the name of the Mac feature that makes these finger motions available to perform specific functions on a Mac OS system:

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3 years ago