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Nataliya [291]
3 years ago
8

You have a piece of rope that is 10 feet long. You want to cut it into 1 3/4 foot pieces. How many pieces can you make and how m

uch is left over​
Mathematics
1 answer:
dexar [7]3 years ago
3 0

Answer:

5 whole number, 5/7

Step-by-step explanation:

10 ÷ 1 3/4

10 ÷ 7/4

10 x 4/7

40/7 or 5 5/7

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Please help me lol ......................
IrinaK [193]

Answer:

A

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A playground merry-go-round of radius R = 1.80 m has a moment of inertia I = 255 kg · m2 and is rotating at 9.0 rev/min about a
Degger [83]

Answer:

7 rpm = 0.73 rad/s

Step-by-step explanation:

R = Radius of merry-go-round = 1.8 m

I_M= Moment of inertia of merry-go-round = 255 kg m²

I_C= Moment of inertia of child

ω = 9 rev/min

m = Mass of child = 24 kg

From the conservation of angular momentum

I\omega=I'\omega '\\\Rightarrow I\omega=(I_M+I_C)\omega'\\\Rightarrow \omega'= \frac{I\omega}{(I_M+I_C)}\\\Rightarrow \omega'=\frac{I\omega}{(I_M+mR^2)}\\\Rightarrow \omega'=\frac{255\times 9}{(255+24\times 1.8^2)}\\\Rightarrow \omega'=6.9\ rev/min

∴ New angular speed of the merry-go-round is 7 rpm = 7\times \frac{2\pi}{60}=\mathbf{0.73\ rad/s}

3 0
4 years ago
PLEASE HELP!
Aleksandr-060686 [28]

The equation of the function f(x) is f(x) = 2 sin(π/2(x + 6)) - 3

<h3>How to create the sine function?</h3>

A sine function is represented as:

f(x) = A sin(B(x + C)) + D

Where

A = Amplitude

Period = 2π/B

C = Phase shift

D = Vertical shift

The requirements in the question are:

  • Amplitude not equal to 1
  • Period not equal to 2π
  • Non-zero phase and vertical shifts

So, we can use the following assumptions

A = 2

Period = 4

C = 6

D = -3

So, we have:

f(x) = 2 sin(B(x + 6)) - 3

The value of B is

4 = 2π/B

This gives

B = π/2

So, we have:

f(x) = 2 sin(π/2(x + 6)) - 3

<h3>The amplitude, vertical shift, period of f(x)and the phase shift</h3>

Using the representations in (a), we have:

  • Amplitude = 2
  • Vertical shift = -3
  • Period = 4
  • Phase shift = 6

<h3>The graph of the function</h3>

See attachment for the graph of f(x)

<h3>The value of cos θ </h3>

Let θ = 3π

So, we have:

cos(3π)

This is calculated as:

cos(3π) = cos(2π + π)

Expand

cos(3π) = cos(2π) *cos(π) - sin(2π) *sin(π)

Evaluate

cos(3π) = -1

<h3>The value of sin θ </h3>

Let θ = 3π

So, we have:

sin(3π)

This is calculated as:

sin(3π) = sin(2π + π)

Expand

sin(3π) = sin(2π) *cos(π) + cos(2π) *sin(π)

Evaluate

sin(3π) = 0

<h3>The value of tan 2θ </h3>

Let θ = 3π

So, we have:

tan(2 * 3π)

tan(6π)

This is calculated as:

tan(6π) = tan(3π + 3π)

Evaluate

tan(3π) = 0

Read more about sinusoidal functions at:

brainly.com/question/10700288

#SPJ1

6 0
2 years ago
Can someone help me out on this :P
irakobra [83]
35 is the answer of right please heart or comment
3 0
4 years ago
Read 2 more answers
In 2001 , chipper had 102 runs batted in. In 2008, Chipper had only 75 runs batted in. Calculate the percent change in runs batt
DerKrebs [107]

Answer:

The percent change in runs batted in from 2001 to 2008 is 26.47%

Step-by-step explanation:

The number of runs chipper batted in the year 2001  = 102 runs

The number of runs chipper batted in the year 2008  = 75 runs

Here, so the Change in the runs batted

= Runs Batted in year 2001 - Runs batted in the year 2008

= 102 runs - 75 runs  =  27 runs

Now, The percentage change in the run = = \frac{\textrm{Change in the batted run from 2001 to 2008}}{\textrm{Total number of batted runs in 2001}}  \times 100

= \frac{27}{102}  \times 100 = 26.47

or, The percentage change = 26.47%

Hence, the percent change in runs batted in from 2001 to 2008 is 26.47%

5 0
3 years ago
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