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bulgar [2K]
3 years ago
14

Help please this is due tomorrow

Mathematics
1 answer:
Travka [436]3 years ago
4 0

Answer:

idfk Imao

Step-by-step explanation:

try working on drawing it out and then finding the with x hype

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A line passes through the point (0, –1) and has a slope of -2/3 What is the equation of the line?
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y=-\dfrac{2}{3}x-1
Answer: A.

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The answer should be -3
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EASY TRIG - 15 POINTS
poizon [28]

Answer: The answers are (a) 40 cm and (b) \sin^{-1}\dfrac{23}{62}.


Step-by-step explanation: The calculations are as follows:

(a) See the figure (a). As given in the question, A circle with centre 'O' circumscribes a triangle ABC with BC = 20 cm and ∠BAC = 30°. We need to find the diameter DC of the circle.

Let us draw BD. Now, ∠BAC and ∠BDC are angles on the same arc BC, so we have

∠BAC = ∠BDC = 30°.

Also, ∠CBD = 90°, since it stands on the diameter DC. So, ΔBCD will be a right angled triangle.

We can write

\sin \angle BDC=\dfrac{BC}{DC}\\\\\\ \Rightarrow \sin 30^\circ=\dfrac{20}{DC}\\\\\\\Rightarrow \dfrac{1}{2}=\dfrac{20}{DC}\\\\\\\Rightarrow DC=40.

Thus, the diameter of the circle = 40 cm.


(b) See the figure (b).

As given in the question, A circle with centre 'O'' circumscribes a triangle DEF with EF = 4.6 inches and diameter GF = 12.4 in.. We need to find the angle EDF.

Let us draw GE. Now, ∠EGF and ∠EDF are angles on the same arc EF, so we have

∠EGF = ∠EDF = ?

Also, ∠GEF = 90°, since it stands on the diameter GF. So, ΔGEF will be a right angled triangle.

We can write

\sin \angle EGF=\dfrac{EF}{GF}\\\\\\ \Rightarrow \sin \angle EGF=\dfrac{4.6}{12.4}\\\\\\\Rightarrow \sin \angle EGF=\dfrac{23}{62}\\\\\\\Rightarrow \angle EGF=\sin^{-1}\dfrac{23}{62}.

Thus,

\angle EDF=\angle EGF=\sin^{-1}\dfrac{23}{62}.

4 0
3 years ago
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