Answer:
x° = 149°
Step-by-step explanation:
According to the <u>Triangle Sum Theorem</u>, the sum of the measures of the angles in every triangle is 180°. Since we are given two angles with measures of m < 86° and m < 63°, then the third angle must be:
m < 86° + m < 63° + m < (angle 3) = 180°
149° + m < ? = 180°
Subtract 149° from both sides to solve for m < (angle 3)
149° - 149° + m < (angle 3) = 180° - 149°
m < ? = 31°
Therefore, the measure of the third angle is 31°.
To find x°, we can reference the <u>Triangle Exterior Angle Postulate</u>, which states that the measure of an exterior angle of a triangle is equal to the sum of the measures of the remote interior angles.
In other words, the measure of x° = m < 86° + m < 63°
x° = 149°
By the way, m< (angle 3) and x° are also supplementary angles whose sum equal 180°:
x° + m < (angle 3) = 180°
149° + 31° = 180°
A^2 + b^2 = c^2...a and b are the legs and c is the hypotenuse
20^2 + 21^2 = c^2
400 + 441 = c^2
841 = c^2
sqrt 841 = c
29 = c <== third straw will be 29 cm
Split up the interval [0, 2] into 4 subintervals, so that
![[0,2]=\left[0,\dfrac12\right]\cup\left[\dfrac12,1\right]\cup\left[1,\dfrac32\right]\cup\left[\dfrac32,2\right]](https://tex.z-dn.net/?f=%5B0%2C2%5D%3D%5Cleft%5B0%2C%5Cdfrac12%5Cright%5D%5Ccup%5Cleft%5B%5Cdfrac12%2C1%5Cright%5D%5Ccup%5Cleft%5B1%2C%5Cdfrac32%5Cright%5D%5Ccup%5Cleft%5B%5Cdfrac32%2C2%5Cright%5D)
Each subinterval has width 
. The area of the trapezoid constructed on each subinterval is 
, i.e. the average of the values of 
at both endpoints of the subinterval times 1/2 over each subinterval ![[x_i,x_{i+1}]](https://tex.z-dn.net/?f=%5Bx_i%2Cx_%7Bi%2B1%7D%5D)
.
So,
Answer:
B
Step-by-step explanation:
The most reasonable one is B because its 7 for side B and the rest for B are either bigger or equal to the given number
Answer:70
Step-by-step explanation:
