Slope-intercept form:
y=mx+b
m=slope
b=y-intercept
Data:
m=4/5
b=-1
y=mx+b
y=(4/5)x-1
Answer: the equation of the line with slope=4/5, and y-intercept=-1 would be:
y=(4/5)x-1
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
7.380 times 10 to the 9th power (or 7.38 times 10 to the 9th power)
