Hi hi!! please help, it’s 8th grade algebra
2 answers:
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The price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25
<em><u>Solution:</u></em>
Let d" be the price of 1 drink
Let "p" be the price of 1 pretzel
Given that, Isabella went into a movie theater and bought 3 drinks and 10 pretzels, costing a total of $54.50
<em><u>Therefore, we can frame a equation as,</u></em>
3 x price of 1 drink + 10 x price of 1 pretzel = 54.50
3d + 10p = 54.5 ---------- eqn 1
Jason went into the same movie theater and bought 9 drinks and 5 pretzels, costing a total of $57.25
9 x price of 1 drink + 5 x price of 1 pretzel = 57.25
9d + 5p = 57.25 ---------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Multiply eqn 1 by 3
9d + 30p = 163.5 ----- eqn 3
<em><u>Subtract eqn 2 from eqn 3</u></em>
9d + 30p = 163.5
9d + 5p = 57.25
( - ) -----------------------
25p = 106.25
p = 4.25
<em><u>Substitute p = 4.25 in eqn 1</u></em>
3d + 10(4.25) = 54.5
3d + 42.5 = 54.5
3d = 54.5 - 42.5
3d = 12
d = 4
Thus price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25
Answer:
Option A is correct.
i.e. x = 1, x = 0 is an extraneous solution.
Step-by-step explanation:
Given the expression
Solving the rational function
Apply fraction across multiply: if
Subtract x(4x+1) from both sides
Simplify
5x² - 4x² - x = 0
x² - x = 0
Factor x² - x = x(x-1)
so
x(x-1) = 0
Using the zero factor principle
if ab=0, then a=0 or b=0 (or both a=0 and b=0)
Thus, the solution to the equation is:
But, it is clear that if we substitute x = 0, the equation becomes undefined because we can not have the denominator to be 0.
In other words, the equation is undefined for x = 0
Thus, x = 0 is an extraneous solutions.
Therefore, option A is correct.
i.e. x = 1, x = 0 is an extraneous solution.