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2 years ago

What is -3(-4a-2)???

Mathematics

2 answers:

AleksAgata [21]2 years ago

3 0

Answer:

-3(-4a - 2) = 12a + 6

nordsb [41]2 years ago

3 0

Answer:

-3(-4a - 2) = 12a + 6

Step-by-step explanation:

-3(-4a - 2)

=> multiply -3 by everything in the parenthesis

-3 * -4a = 12a

-3 * -2 = 6

=> combine like terms

12a + 6

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3 years ago

Read 2 more answers

A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 340 babies were born, a

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Answer:

The 99% confidence interval estimate of the percentage of girls born is (0.8, 0.9).

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Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

In the study 340 babies were born, and 289 of them were girls. This means that $n = 340, \pi = \frac{289}{340} = 0.85$

Use the sample data to construct a 99% confidence interval estimate of the percentage of girls born.

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 - 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.80$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 + 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.90$

The 99% confidence interval estimate of the percentage of girls born is (0.8, 0.9).

Does the method appear to be effective?

b)Yes, the proportion of girls is significantly different from 0.5.

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3 years ago