Answer:
Option D is the correct answer for the above question.
Explanation:
Email list (as the name suggests) is defined as the set of an Email address. It is also the group of address which is needs for message distribution because an Email address is the only necessary part to send the mail which is also called the message. When a user wants to send the mass Email or message then he needs a list of email which can be filled at the "TO" or "CC" or "BCC" part of the compose mail and it can be able to send the mass message.
The above question asked about the list which is useful for the mass message then the answer is an Email list which is stated from the option D. Hence option D is the correct answer while other is not because--
- Option A states the actor list which is not required to send the mail.
- Option B states the client list which is not required to send the mail.
- Option C states the chat list which is not required to send the mail.
Answer:
Explanation:
Since all of the items in the array would be integers sorting them would not be a problem regardless of the difference in integers. O(n) time would be impossible unless the array is already sorted, otherwise, the best runtime we can hope for would be such a method like the one below with a runtime of O(n^2)
static void sortingMethod(int arr[], int n)
{
int x, y, temp;
boolean swapped;
for (x = 0; x < n - 1; x++)
{
swapped = false;
for (y = 0; y < n - x - 1; y++)
{
if (arr[y] > arr[y + 1])
{
temp = arr[y];
arr[y] = arr[y + 1];
arr[y + 1] = temp;
swapped = true;
}
}
if (swapped == false)
break;
}
}
Building relationships during your career exploration is called networking. This is when you are forming relations with those around you so that opportunities may turn up.
Your answer is: Networking
Have an great day mate!
Answer:
// program in Python to check perfect number
#function to find number is perfect or not
def is_Perfect_Number(n):
#total variable
tot = 1
i = 2
#sum of all divisor of number
while i*i<=n:
if n%i==0:
tot = tot + i + n/i
if tot == n and n != 1:
return 1
i = i+1
return 0
#read until user enter a perfect number
while True:
#read integer
num = int(input("Input an integer: "))
#call the function
if(is_Perfect_Number(num)):
print(num,"is perfect number")
#if perfect number break
break
else:
print(num,"is not a perfect number")
#ask again
print("try again.")
Explanation:
Read number from user and then call the function is_Perfect_Number() with parameter "num".This will find the sum of all divisor of number.If sum is equal to number then it will return 1 else return 0.If the number is not perfect then it will again ask to enter a number until user enter a perfect number.
Output:
Input an integer: 24
24 is not a perfect number
try again.
Input an integer: 28
28 is perfect number
Answer:
def normalize(text):
text = text.lower()
text = text.split()
return text
Explanation:
The functiinfunction is provided with an input text when called upon, then it changes every character in the text into lower case and split each word with a space.
