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3 years ago

If two cylinders have the same radius, but one has a height two times larger

Mathematics

1 answer:

sweet [91]3 years ago

5 0

The volume of the large cylinder will be twice the volume of the small cylinder.

<u>Step-by-step explanation:</u>

Let the radius of the cylinder be 'r'

Let the height of the cylinder be'h'

Volume of the small cylinder=π r² h

Volume of the large cylinder= π r² (2h)

Volume of large cylinder/volume of small cylinder= 2/1

The large cylinder volume is twice the volume of the small cylinder.

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alukav5142 [94]

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1.25•3= 3.75 or 3 3/4

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3 years ago

Please help me !??!!!

iris [78.8K]

Answer:

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Step-by-step explanation:

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2 years ago

an article after allowing a discount of 20% on its marked price was sold at a gain of 20% had it been sold after allowing 25% di

Effectus [21]

Answer:

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Step-by-step explanation:

Let MP = m

Discount = 25% of MP = m/4

SP = MP - Discount

= m - m/4 = 3m/4

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8 0

3 years ago

Solve the equation. StartFraction dy Over dx EndFraction equals5 x Superscript 4 Baseline (1 plus y squared )Superscript three h

dangina [55]

Answer:

Step-by-step explanation:

To solve the differential equation

dy/dx = 5x^4(1 + y²)^(3/2)

First, separate the variables

dy/(1 + y²)^(3/2) = 5x^4 dx

Now, integrate both sides

To integrate dy/(1 + y²)^(3/2), use the substitution y = tan(u)

dy = (1/cos²u)du

So,

dy/(1 + y²)^(3/2) = [(1/cos²u)/(1 + tan²u)^(3/2)]du

= (1/cos²u)/(1 + (sin²u/cos²u))^(3/2)

Because cos²u + sin²u = 1 (Trigonometric identity),

The equation becomes

[1/(1/cos²u)^(3/2) × 1/cos²u] du

= cos³u/cos²u

= cosu

Integral of cosu = sinu

But y = tanu

Therefore u = arctany

We then have

cos(arctany) = y/√(1 + y²)

Now, the integral of the equation

dy/(1 + y²)^(3/2) = 5x^4 dx

y/√(1 + y²) = x^5 + C

y - (x^5 + C)√(1 + y²) = 0

is the required implicit solution

5 0

3 years ago

The function f(x) is represented by this table of values.

Darya [45]

The average slope (s) on the interval [a, b] is given by
s = (f(b) -f(a))/(b -a)

When there are a lot of computations to do, it is convenient to let a machine do them. The intervals and slopes are ...
[0, 5] : 5
[-3, 3] : 0
[-5, 3] : -2
[-3, 5] : 2

6 0

3 years ago