If two cylinders have the same radius, but one has a height two times larger
1 answer:
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Answer:
10 Square Inches
Step-by-step explanation:
<u>Trapezoid</u>
Base =12 inches
Height =10 inches
Top side= 10 inches.
Area of a Trapezoid
Area of the Trapezoid=110 Square Inches
<u>Rectangle</u>
Base = 12 inches
Height =10 inches.
Area of a Rectangle=Base X Height
=12 X 10
=120 Square Inches
<u>Difference in Area between the two packages</u>
Difference=Area of Rectangle-Area of Trapezoid
=120-110
=10 Square Inches
Answer:
y = 1/2 x -2
Step-by-step explanation:
rise/run from (-6, -5) to (-4, -4) = 1/2
(rise 1, run 2)
meaning that slope (m) = 1/2
we can now rewrite our points in y=mx + b formatting:
y = mx + b
-5 = (1/2)(-6) + b
-4 = (1/2)(-4)+b
now, let's solve for b
-5 = (1/2)(-6) + b
-5 = -3 + b
-2 = b
-4 = (1/2)(-4)+b
-4 = -2 + b
-2 = b
So, the equation for our line is y = x- 2
hope this helps!! have a lovely day :)
Answer:
Step-by-step explanation:
Convert 11 ft to inches by multiplying by 12 (number of inches in a foot)
Now find the area: