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jonny [76]
3 years ago
15

If two cylinders have the same radius, but one has a height two times larger

Mathematics
1 answer:
sweet [91]3 years ago
5 0

The volume of the large cylinder will be twice the volume of the small cylinder.

<u>Step-by-step explanation:</u>

Let the radius of the cylinder be 'r'

Let the height of the cylinder be'h'

Volume of the small cylinder=π r² h

Volume of the large cylinder= π r² (2h)

Volume of large cylinder/volume of small cylinder= 2/1

The large cylinder volume is twice the volume of the small cylinder.

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Because segments AB and BC are congruent, their corresponding angles (<BAD and <BCD) would also be congruent to each other, meaning that both would be 56°.

Knowing that triangles add up to 180°, the whole triangle (ABC) would then have 2 angles that are 56° and the top angle (<ABC) would be 68°

Splitting those in half ( because <ABD and <CBD are congruent), each would be 34° (thus x=34°)

Looking now at the two separate triangles (ABD and CBD), we can determine that both <BDA and <BDC are 90° (right angles) because 180-34-56=90°.

Therefore, since both triangles have all congruent angles, both triangles are the same! So, since segment AD=5, segment CD would also be 5 (y=5).

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