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Ilya [14]
3 years ago
7

Please answer this simple question !!!

Mathematics
1 answer:
Nastasia [14]3 years ago
6 0
The final answer is (2,1).

Step 1: Solve for either x or y in one of the two equations.

     x + 3y = 5
         - 3y  - 3y
----------------------
     x = -3y + 5
  

Step 2: Substitute the expression you got for x into the opposite equation.

-3y + 5 - 3y = -1
  -6y + 5 = -1
         - 5    - 5
--------------------
  -6y = -6
 ------  -----
  -6       6
 
    y = 1


Step 3: Plug in the solution you got for y into either of the 2 equations.

x + 3(1) = 5
  x + 3 = 5
      - 3  - 3
---------------
  x = 2





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vazorg [7]
<span>With no digit being repeated: 10*9*8*7*6= 30,240</span>
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How much money is 1/2 of $11.00<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1" title=" \frac
never [62]

$5.5

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½ × 11.00

5.5

Hope this helps. Have a good day!

6 0
3 years ago
Read 2 more answers
Select all the ratios that are equivalent to the ratio 12 : 3. Explain how you know.
oksano4ka [1.4K]

Answer:

the answers are c, d, &f

Step-by-step explanation:

the equivalence to 12:3

1200:300. = 12:3 (reduce by 100)

12:3= 4:1 (reduce by 3)

24:6= 12:3 (reduce by 2)

3 0
3 years ago
Read 2 more answers
Find the product<br> (2n-2)(2n^2-3n+5)
atroni [7]

Answer:

  4n^3 -10n^2 +16n -10

Step-by-step explanation:

Use the distributive property to eliminate parentheses, then combine like terms.

  = 2n(2n^2 -3n +5) -2(2n^2 -3n +5)

  = 4n^3 -6n^2 +10n -4n^2 +6n -10

  = 4n^3 +n^2(-6-4) +n(10+6) -10

  = 4n^3 -10n^2 +16n -10

4 0
3 years ago
Please help asap find f -1
ExtremeBDS [4]
I.
Given a function f with domain D and range R, and the inverse function 
f ^{-1},

then the domain of f ^{-1} is the range of f, and the range of f ^{-1} is the domain of f.

II. We are given the function f(x)= \sqrt{x-5},

the domain of f, is the set of all x for which \sqrt{x-5} makes sense, so x is any x for which x-5\geq0, that is x≥5.

the range is the set of all values that f can take. Since f is a radical function, it never produces negative values, in fact in can produce any value ≥0

Thus the Domain of f is [5, ∞) and the Range is [0, ∞)
then , the Domain of f ^{-1} is [0, ∞) and the Range of f ^{-1} is [5, ∞) 

III.
Consider f(x)= \sqrt{x-5}

to find the inverse function f^{-1}, 

1. write f(x) as y:

y= \sqrt{x-5}

2. write x in terms of y:

y= \sqrt{x-5}

take the square of both sides

y^{2} =x-5

add 5 to both sides

y^{2} +5=x

x=y^{2} +5

3. substitute y with x, and x with f^{-1}(x):

f^{-1}(x)=x^{2} +5


These steps can be applied any time we want to find the inverse function.

IV. Answer: 

f^{-1}(x)=x^{2} +5, x≥0

y≥0, where y are all the values that f^{-1} can take

Remark: the closest choice is B

8 0
3 years ago
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