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frosja888 [35]
3 years ago
7

Find the missing length of the right triangle. a 21 35

Mathematics
1 answer:
WITCHER [35]3 years ago
4 0

Answer:

28

Step-by-step explanation:

Use the pythagorean theorem and solve for a:

a² + b² = c²

a² + 21² = 35²

a² + 441 = 1225

a² = 784

a = 28

So, the missing length is 28.

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In an annual celebration, 674 students participated. Of them 392 were boys. Find the number of girls who participated.
VARVARA [1.3K]
674-392=282 so the answer would be 282 girls who participated
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3 years ago
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What would be the equation of the midline of this graph?
andrey2020 [161]

Answer:

Step-by-step explanation:

Vertices of the quadrilateral ABCD are,

A → (-5, 2)

B → (-3, 4)

C → (-2, 4)

D → (-1, 2)

By reflecting the given quadrilateral ABCD across x-axis to form the image quadrilateral A'B'C'D',

Rule for the reflection of a point across x-axis is,

(x, y) → (x , -y)

Coordinates of the image point A' will be,

A(-5, 2) → A'(-5, -2)

From the picture attached, point E is obtained by translation of point A'.

Rule for the translation of a point by h units right and k units up,

A'(x+h, y+k) → E(x', y')

By this rule,

A'(-5 + h, -2 + k) → E(1, -1)

By comparing coordinates of A' and E,

-5 + h = 1

h = 6

-2 + k = -1

k = 1

That means

Rule for the translation will be,

[(x + 6), (y + 1)]

5 0
3 years ago
Can anyone answer the questions asked in the picture?
Marina CMI [18]
The greatest number of binders is 5, the greatest number of notebooks is 10. If she buys 7 notebooks then she can only buy 1.
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3 years ago
Priya noticed in the last activity that between the 2 triangles, you only need to know 4 angles to show that they are similar. S
ValentinkaMS [17]

Answer:

Please find attached a drawing of the triangles ΔRST and EFG showing the angles

The angle on ΔEFG that would prove the triangles are similar is ∠F = 25°

Step-by-step explanation:

In order to prove that two triangles are similar, two known angles of each the triangles need to be shown to be equal

Given that triangle ∠R and ∠S of triangle ΔRST are 95° and 25°, respectively, and that ∠E of ΔEFG is given as 90°, then the corresponding angle on ΔEFG to angle ∠S = 25° which is ∠F should also be 25°

Therefore, the angle on ΔEFG that would prove the triangles are similar is ∠F = 25°.

3 0
3 years ago
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