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frosja888 [35]
2 years ago
7

Find the missing length of the right triangle. a 21 35

Mathematics
1 answer:
WITCHER [35]2 years ago
4 0

Answer:

28

Step-by-step explanation:

Use the pythagorean theorem and solve for a:

a² + b² = c²

a² + 21² = 35²

a² + 441 = 1225

a² = 784

a = 28

So, the missing length is 28.

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Solve this question ​
love history [14]

Answer:

\frac{4x - 11}{2}  \leqslant 3x - 3 < 4 \\  \\   =  > \frac{4x - 11}{2}  \leqslant 3x - 3 \: and \: 3x - 3 < 4 \\  \\  <  =  > 4x - 11 \leqslant 6x - 6 \:  \: and \:  \: 3x < 7 \\  \\  <  =  > 2x \geqslant  - 5 \:  \: and \:  \: x <  \frac{7}{3}  \\  \\  <  =  >  \frac{ - 5}{2}  \leqslant x <  \frac{7}{3}

=> the greatest integer is 2

the smallest integer is -2

3 0
3 years ago
Given: SSA triangle, A=62°, a=5cm, b=15cm.
sattari [20]
I’m sure your answer it’s the second one 48:70:24.3 cm
5 0
2 years ago
Consider the graph of the function f(x)=2x.
77julia77 [94]

Given:

The parent function is:

f(x)=2^x

The other function is:

g(x)=2f(x)

To find:

The statement that describes a key feature of function g.

Solution:

We have,

f(x)=2^x

g(x)=2f(x)

Using these two functions, we get

g(x)=2(2)^x

Putting x=0, we get

g(x)=2(2)^{(0)}

g(x)=2(1)

g(x)=2

The y-intercept of the function g at (0,2). So, option A is correct and option B is incorrect.

We know that g(x)\to 0 as x\to -\infty and it will never intersect the line y=0. It means the horizontal asymptote of the function g is

Therefore, the correct option is A.

3 0
2 years ago
Read 2 more answers
does somebody knows how to do this one?
vlada-n [284]

Answer:

Step-by-step explanation:

To find the area subtract the area of the semicircle from the area of the rectangle.

Although the line isn’t there, if you imagine there is one, then you will see that you form a rectangle which is the same line as the semicircle’s diameter.

The area of rectangle is:

⇒ A = lw

⇒ A = (14)(8)

⇒ A = 112cm^{2}

The area of the semicircle;

⇒ A = \frac{1}{2}\pi r^{2}

⇒ A = \frac{1}{2}\pi (7)^{2}

*Note here that the radius is half the diameter, so it is 7cm, not 14cm

⇒ A = 76.97cm^{2}

Finally subtract the two areas;

⇒ A = 112 - 76.97

⇒ A = 35.03cm^{2}

6 0
2 years ago
What equation does the model represent
lara [203]
5 whole and 1/6 hope it help you
8 0
2 years ago
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