Answer:
Therefore the required rule for the given table is

Step-by-step explanation:
Given :
Table values are
x y
6 -12
7 -14
8 -16
9 -18
10 -20
To Find :
The rule for above result = ?
Solution:
The Required Rule for the above Table is

For first case
Put x = 6 in the rule we get
as shown in the table
For second case
Put x = 7 in the rule we get
as shown in the table
For third case
Put x = 8 in the rule we get
as shown in the table
For fourth case
Put x = 9 in the rule we get
as shown in the table
For fifth case
Put x = 10 in the rule we get
as shown in the table
Therefore the required rule for the given table is

The triangles in question 15 are proportional, so they are similar. Meaning that their angles are the same, so <B=<E, or <B=30 degrees.
For #17, the formula for the area of a circle is a=pi*r^2. The radius, in this instance, is 1/2 of 27, or 13.5. Plug it into the formula: a=pi*13.5^2. a=pi*182.25. If you want to simplify it further, a=572.265.
#19, same formula as #17. a=pi*r^2. a=pi*6^2. a=pi*36. a=113.04 or 113m^2.
#20, Wow this is a complicated one. Anyway, the area of the square in the middle is obviously 9m. The area of all of the circles is a=pi*1.5^2 DIVIDED BY TWO, since they're half circles. a=pi*2.25/2, a=7.065/2. a=3.5325. Since there are 4 of them, multiply that number by 4... 14.13. Add 9 to that to get the area of the whole figure: 23.13m(^2). Hope this helps.
Answer:
10
Step-by-step explanation:
median is the middle number
these numbers in order are 2, 5, 6, 8, 12, 15, 19, 22 and the middle numbers are 8 and 12
to ind the middle number of those two numbers, you find the mean (averge) of those numbers
mean: 8+12=20/2=10
lmk if its right!
Percent formula : is/of = %/100
% = n
is = 23
of = 94
now we just sub our numbers into the formula
23/94 = n/100 <===
Hello there!
Remember the Negative Exponent Law. If we have a number with a negative exponent, we flop it over.
So our answer looks like so:

<h2>Therefore, our answer is:

</h2>
Hope this helps you!
~Just a felicitous girlie
#HaveASplendidDay
