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2 years ago

What's the area of these?

Mathematics

1 answer:

kvasek [131]2 years ago

6 0

Left side: 63, 72, 16 right side: 36, 4, 35

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Please answer this correctly

aleksley [76]

Answer:

16 ounces of clay he need.

Step-by-step explanation:

Given:

Reggie had 2-pound bricks of clay and his job is to give 4 ounces of clay to each student.

There are total 28 students.

Now, to get how much ounces of clay does the each student have first we multiply the number of students to the number of ounces of clay.

Number of students × Number of ounces of clay:

$28\times 4$

$112$

Now, total amount of clay ounces Reggie had= 3×32=96 ounces. (1 pound = 16 ounces, 2 pound = 32 ounces.)

So, the total amount of clay he need is = $112-96$

= $16$

Therefore, 16 ounces of clay he need.

6 0

2 years ago

Read 2 more answers

Find x and the measure of each side.

Anna71 [15]

Answer:

x=27.5

FG=72.5

GH=60

HF=47.5

Step-by-step explanation:

Sum of angles in a triangle=180

Therefore, FG+GH+HF=180

Substituting the values we have,

(3x - 10) + (2x+5) +(x+20) = 180

Collecting like terms

3x+2x+x = 180 +10 - 5 - 20

6x = 165

X= 27.5

FG = (3x - 10) = 3(27.5) - 10

FG= 72.5

GH= (2x+5) = 2(27.5)+5

GH=60

HF= x+20 =27.5+20

HF=47.5

5 0

10 months ago

The difference of four times a number and seven is thirteen

Scrat [10]

4n - 7 = 13

4n = 20
n = 5. Hope it helps!

6 0

2 years ago

Complete the

nydimaria [60]

Answer:

8th: 23

11th: 32

15th: 44

22nd: 65

18th: 53

Step-by-step explanation:

The pattern is adding 3 each time:

2, 5, 8, 11, 14, 17, 20, 23, 26, 29, 32, 35, 38, 41, 44, 47, 50, 53, 56, 59, 62, 65

Hope it helps!

4 0

2 years ago

Drag and drop formal proof. Prove the Polygon Exterior Angle Sum Theorem for the enclosed triangle, that is ∠1+∠2+∠3=360°

jasenka [17]

Answer:

The sum of all the external angles of a triangle is 360°.

Step-by-step explanation:

Let there are n sides in a polygon.

So, there are n internal angles in the polygon, let ∠i1, ∠i2, ∠i3, ..., ∠in are the measure of n internal angles of the polygon.

The measure of external angle corresponding to ∠i1, ∠1= 180°-∠i1,

The measure of external angle corresponding to ∠i2, ∠2 = 180°-∠i2,

Similarly, the measure of external angle corresponding to ∠in, ∠n = 180°-∠in.

Now, the sum of all the external angles of the polygon,

(∠1+∠2+...+∠n)=(180°-∠i1)+(180°-∠i2)+...+(180°-∠in)

=(180°+180°+...n times)-(∠i1+∠i2+...+∠in)

=n x 180° - (∠i1+∠i2+...+∠in)

As ∠i1+∠i2+...+∠in is the sum of all the internal angles of the polygon.

So, the sum of all the external angles of the polygon =

(n x 180°) - (sum of all the internal angles of the polygon).

In the case of a triangle, n=3 and the sum of all the three internal angles, ∠i1+∠i2+∠i3 = 180°.

Therefore, the sum of all the external angles of a triangle,

∠1+∠2+∠3 =3x180°-(∠i1+∠i2+∠i3)

=540°=180°

=360°.

Hence, the sum of all the external angles of a triangle is 360°.

5 0

2 years ago