Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Answer:
Step-by-step explanation:
your welcome
If you follow the order of pemdas the answer would be (-24)
She bought 4 brushes at $3 each
And 8 tubes of paint at $ .50 each
3x4=12
.50x8=4
12+4=16
The temperature was -14°F at 8 a.m.
At noon is was 10 degrees warmer - the temperature increase was 10°F
-14°F + 10°F = -4°F
The tempertaure increase between noon and 4 p.m. was twice the previous increase in temperature, which was 10°F.
10°F x 2 = 20°F
We want to know the temperature at 4 p.m. so we just add it up to the previous result.
-4°F + 20°F = 16°F
16°F is the correct answer
